- #1
Dethrone
- 717
- 0
I've always been having trouble with the domain and range of inverse trigonometric functions. For example, let's start with an easy one: $\sin^{-1}\left({x}\right)$
Process: First, I draw out the function of $\sin\left({x}\right)$. Then I look at its range and attempt to restrict it so that it is invertible, which is from $\frac{-\pi}{2}$ to $\frac{\pi}{2}$. Now to draw the graph, I have to rotate it by the axis $y=x$...I can't seem to visualize how to do that...Do I turn my page sideways?
Let's try another one: $\sec^{-1}\left({x}\right)$
Drawing $\sec\left({x}\right)$ first, I look at its asymptotes which are when $\cos\left({x}\right)$ is equal to $0$ on... Does someone actually go through all this work to find the domain and range of $\sec^{-1}\left({x}\right)$? Or do they have it memorized?
This seems very tedious and a lot of work to know the domain and range of inverse functions. Is there a quicker way? (Wondering)
Process: First, I draw out the function of $\sin\left({x}\right)$. Then I look at its range and attempt to restrict it so that it is invertible, which is from $\frac{-\pi}{2}$ to $\frac{\pi}{2}$. Now to draw the graph, I have to rotate it by the axis $y=x$...I can't seem to visualize how to do that...Do I turn my page sideways?
Let's try another one: $\sec^{-1}\left({x}\right)$
Drawing $\sec\left({x}\right)$ first, I look at its asymptotes which are when $\cos\left({x}\right)$ is equal to $0$ on... Does someone actually go through all this work to find the domain and range of $\sec^{-1}\left({x}\right)$? Or do they have it memorized?
This seems very tedious and a lot of work to know the domain and range of inverse functions. Is there a quicker way? (Wondering)