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Homework Statement
Basically I'm just trying to convert a double integral into polar coordinates, but when I do it I get confused with my bounds.
Homework Equations
The Attempt at a Solution
[tex]4\int_0^{\infty}\int_0^{\infty}e^{-(u^2+v^2)}u^{2x-1}v^{2y-1}dudv[/tex]
(x and y are just numbers, not variables). Then I transform the integral given polar coordinates [tex]u=r\cos\theta, v=r\sin\theta[/tex] and I get
[tex]4\int_a^b\int_c^d e^{-r^2}(r\cos\theta)^{2x-1}(r\sin\theta)^{2y-1}rdrd\theta=4\int_a^b\int_c^d e^{-r^2}r^{2(x+y)-1}\cos^{2x-1}\theta\sin^{2y-1}\theta drd\theta[/tex].
I know that [tex]a=0,b=\infty,c=0,d=\frac{\pi}{2}[/tex] so that the integral bounds are [tex]\int_0^{\infty}\int_0^{\pi/2}f(r,\theta)rdrd\theta[/tex], but I can't seem to understand the reasoning behind the bounds. Thanks for your help!
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