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Where? I don't see it.mrcleanhands said:Homework Statement
https://docs.google.com/file/d/0BztURiLWDqMyaVplX0tMYUdNNkE/edit?usp=sharing
Homework Equations
The Attempt at a Solution
Solution is given.
Did you draw the graph or have one to look at?I don't understand how +-∏/4 is found as a range for θ
Also why is 0 <= r <= cos2θ
r is always r which is defined as cos2θ
A double integral for loop of rose r=cos2θ is a mathematical concept that involves calculating the area under a curve in polar coordinates. In this particular case, the curve is a rose with the equation r=cos2θ, where r represents the distance from the origin and θ represents the angle.
The main difference between a double integral for loop of rose r=cos2θ and a regular double integral is the use of polar coordinates instead of rectangular coordinates. This means that the limits of integration and the integrand will be expressed in terms of r and θ instead of x and y.
The for loop is used to iteratively calculate the value of the double integral. It breaks down the area under the curve into smaller, rectangular regions and calculates the sum of their areas. This allows for a more accurate approximation of the double integral.
The limits of integration for a double integral for loop of rose r=cos2θ are determined by the shape and size of the region of interest. In this case, the region is a circle with a radius of 1, so the limits for r would be 0 to 1. The limits for θ would depend on the desired angle of rotation, typically from 0 to 2π.
Double integrals for loop of rose r=cos2θ have various applications in physics and engineering, such as calculating the moment of inertia for irregularly shaped objects, determining the center of mass, and finding the electric field generated by a charged ring. They can also be used in computer graphics to create visual effects such as 3D modeling and ray tracing.