- #1
- 4,807
- 32
I am asked to calculate the double integral of the function
[tex]f(x,y) = (2x+3y)^2 = 4x^2 + 12xy + 9y^2[/tex]
on the domain defined by a triangle whose summits(?) are at (-1,0), (0,1) and (1,0). I chose to integrate from left to right. So the bounds of my integral are
[tex]\int_0^1 \int_{y-1}^{1-y} (4x^2 + 12xy + 9y^2)dxdy[/tex]
[tex]f(x,y) = (2x+3y)^2 = 4x^2 + 12xy + 9y^2[/tex]
on the domain defined by a triangle whose summits(?) are at (-1,0), (0,1) and (1,0). I chose to integrate from left to right. So the bounds of my integral are
[tex]\int_0^1 \int_{y-1}^{1-y} (4x^2 + 12xy + 9y^2)dxdy[/tex]