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pc2-brazil
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Homework Statement
For the chemical equilibrium [tex]N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}[/tex] , the following values were found for the constant Kc (chemical equilibrium constant), at the indicated temperatures:
(The table is attached as an image)
Code:
Table in text format:
Temperature (K) Kc (10^-4)
I 1800 1.21
II 2000 4.08
III 2100 6.86
IV 2200 11.0
V 2300 16.9
a) I
b) II
c) III
d) IV
e) V
Homework Equations
General form of the formula for finding the chemical equilibrium constant with respect to the molar concentrations of the reagents and products at the state of equilibrium:
[tex]K_c = \frac{[P]^p}{[R]^r}[/tex]
Where P are the products of the chemical reaction, R are the reagents, [] denotes molar concentration (mol/L) and p and r are the coefficients of each product and reagent in the chemical equation.
The Attempt at a Solution
The expression for the equilibrium constant of the given reaction is:
[tex]K_c = \frac{[NO]^2}{[N_2][O_2]}[/tex]
Where [X] denotes molar concentration of X.
As the concentration of NO, [NO], gets bigger, the fraction with [NO]2 as numerator also gets bigger; so, Kc gets bigger.
Then, the situation where Kc is the biggest should be the one with the highest concentration of NO. In this case, the answer would be letter E) V, since, in V, Kc equals 16.9.
So, the correct answer should be E (the highest Kc).
But the book says the correct answer is A (the smallest Kc), not E.
What is wrong with this reasoning?
Thank you in advance.
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