- #1
Hernaner28
- 263
- 0
1. The proof
2. The doubt
What I don't understand is when he switch the variable back to x. He says that:
[tex] \displaystyle \int_{-a}^{0}{f(x)dx=-\int_{0}^{a}{f(x)dx}}[/tex]
But if we have:
[tex] \displaystyle \int_{0}^{a}{f(-t)dt=-\int_{0}^{a}{f(t)dt}}[/tex]
Then if we switch back to x we should have:
[tex] \displaystyle \int_{-a}^{0}{f(x)dx=\int_{-a}^{0}{f(-x)dx}}[/tex]
And not what he said. Could you clarify that to me?
Thanks!
What I don't understand is when he switch the variable back to x. He says that:
[tex] \displaystyle \int_{-a}^{0}{f(x)dx=-\int_{0}^{a}{f(x)dx}}[/tex]
But if we have:
[tex] \displaystyle \int_{0}^{a}{f(-t)dt=-\int_{0}^{a}{f(t)dt}}[/tex]
Then if we switch back to x we should have:
[tex] \displaystyle \int_{-a}^{0}{f(x)dx=\int_{-a}^{0}{f(-x)dx}}[/tex]
And not what he said. Could you clarify that to me?
Thanks!