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EDIT***: sorry I figured out how to do this problem and don't need help anymore...:\
Disregard and even delete this thread.
A race-car driver buys a car (CAR A) that can accelerate at +5.9 m/s2 . The racer decides to race against another driver with a car (CAR B) that can move with a constant acceleration of +3.6 m/s2. Both start from rest, but CAR B leaves 1.0 s before the driver of CAR A.
Find the time it takes CAR A to overtake CAR B
Find the distance the two drivers travel during this time.
Find the velocities of both cars when they are side by side.
I'm not sure if this is what to use, but
Final velocity = Initial velocity + at
or maybe
d = (initial velocity)(t) + 1/2 (a)(t)2
Because car B has a 1 second lead, it will have established a 3.6 m lead on car A and already entered acceleration when car A gets off the line. I would think then that car B has an initial velocity of 3.6 while car A's is 0. I'm trying to find t where d1=22
So d1 = 0 + 1/2 (5.9)(t)2
d2 = 3.6 + 1/2 (3.6)(t)2
if these are set equal to equal to each other and the first is solved for t, I get t2=2.95
then I plugged this number into the t2 in the other equation and get 3.6 + 1/2(3.6)(2.95)
= 8.91s
Did I do this right?
vvvvv
EDIT***: sorry I figured out how to do this problem and don't need help anymore...:\
Disregard and even delete this thread.
Disregard and even delete this thread.
Homework Statement
A race-car driver buys a car (CAR A) that can accelerate at +5.9 m/s2 . The racer decides to race against another driver with a car (CAR B) that can move with a constant acceleration of +3.6 m/s2. Both start from rest, but CAR B leaves 1.0 s before the driver of CAR A.
Find the time it takes CAR A to overtake CAR B
Find the distance the two drivers travel during this time.
Find the velocities of both cars when they are side by side.
Homework Equations
I'm not sure if this is what to use, but
Final velocity = Initial velocity + at
or maybe
d = (initial velocity)(t) + 1/2 (a)(t)2
The Attempt at a Solution
Because car B has a 1 second lead, it will have established a 3.6 m lead on car A and already entered acceleration when car A gets off the line. I would think then that car B has an initial velocity of 3.6 while car A's is 0. I'm trying to find t where d1=22
So d1 = 0 + 1/2 (5.9)(t)2
d2 = 3.6 + 1/2 (3.6)(t)2
if these are set equal to equal to each other and the first is solved for t, I get t2=2.95
then I plugged this number into the t2 in the other equation and get 3.6 + 1/2(3.6)(2.95)
= 8.91s
Did I do this right?
vvvvv
EDIT***: sorry I figured out how to do this problem and don't need help anymore...:\
Disregard and even delete this thread.
Last edited: