- #1
BillKet
- 313
- 29
Hello! If we have a 2 level system (I will call the states g and e for ground and excited), and a laser field (which can have any detuning relative to the spacing between g and e), it can be shown that that the total number of particles is conserved under the laser-atom interaction hamiltonian, hence when solving for the energy levels one need to look only at pairs of the form [(g,n), (e,n-1)], where n is the number of photon quanta, which gives a 2x2 Hamiltonian that can be solved for and the energies of the system in the presence of the field are obtained.
Can someone point me (or help me understand) towards the same derivation for more than 2 levels (say 3 for now)? In the 3 levels case, we have g, e1, and e2, where e1 and e2 are the 2 excited levels (assume e1<e2). However, I am not sure what states form the irreducible subspace (the equivalent of the [(g,n), (e,n-1)] above). I assume that we have (g,n) but what are the others? I would expect (e1,n-1) and (e2, n-1) basically corresponding to the laser connecting the ground state to e1 and e2 directly, respectively. But I would also imagine (e2,n-2), basically as we use a photon to go from g to e1 and a second one to go from e1 to e2, instead of going from g to e2 directly as above. But of course (e2, n-1) and (e2, n-2) don't have the same number of quantas, so I am not sure if this logic holds. Is (e2,n-2) not allowed? What are the right states in this 3 level case? Thank you!
Can someone point me (or help me understand) towards the same derivation for more than 2 levels (say 3 for now)? In the 3 levels case, we have g, e1, and e2, where e1 and e2 are the 2 excited levels (assume e1<e2). However, I am not sure what states form the irreducible subspace (the equivalent of the [(g,n), (e,n-1)] above). I assume that we have (g,n) but what are the others? I would expect (e1,n-1) and (e2, n-1) basically corresponding to the laser connecting the ground state to e1 and e2 directly, respectively. But I would also imagine (e2,n-2), basically as we use a photon to go from g to e1 and a second one to go from e1 to e2, instead of going from g to e2 directly as above. But of course (e2, n-1) and (e2, n-2) don't have the same number of quantas, so I am not sure if this logic holds. Is (e2,n-2) not allowed? What are the right states in this 3 level case? Thank you!