Dy multiplied by y (order matters?)

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The equation presented for integration is dT=1/2 * [(m/L)dy]*[yx/L]^2, with y as the variable. The integration can be simplified to the form ∫y^2 dy, as the position of dy can be adjusted without affecting the outcome. This approach aligns with standard practices in calculus, where dy is treated as a differential. The integration results in an expression of the form ∫ k y^2 dy, where k is a constant derived from the problem's parameters. Understanding this allows for proper integration and application in the context of the equation.
az91
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Hey all, this is my first post here,

I have a question that is kind of annoying me: I came across this equation:

dT=1/2 * [(m/L)dy]*[yx/L]^2. Only y is a variable here

I need to integrate it, but my question is do I change the location of the dy and solve it as: ∫y^2 dy? I believe that this is what is done in the book but I am not sure if this is correct.

Any help will be appreciated. :D
 
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Yes, it becomes an integral of the form ##\int k\,y^2\,dy## for some constant ##k##, calculated from the parameters in the problem. ##dy## is considered as a differential and its location can be changed without problem.
 

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