E Field and Field Transformations

In summary, the conversation discusses a round, uncharged current loop at rest in the xz plane of IRF K with a nonzero B(y) field at points on the y axis. When viewed from IRF K', there is a nonzero E(z)' field on the y' axis, despite having zero net charge and zero dB(y)’/dt’ at those points. K' moves in the positive x direction of K at speed v and the x/x' axes of the two frames are parallel. The conversation also mentions that the E' field in K' is the superposition of a conservative part and a non-conservative part, and that the loop's charge density does not vanish everywhere when viewed in K'. Finally, the conversation
  • #1
GRDixon
249
0
Note: in the following, parentheses denote "subscript". "G" denotes "gamma".

A round, uncharged current loop is at rest in the xz plane of IRF K. The loop is centered on the Origin. Negative charge circulates around the loop, positive charge remains at rest. There is a nonzero B(y) field at points on the y axis.

Viewed from IRF K’, at time t'=0 dB(y)’/dt’=0 at points on the y’ axis. Yet E(z)’=GvB(y) (where G stands for “gamma”). Since the net charge is zero in K’ (as it is in K), and since dB(y)’/dt’=0 at points on the y’axis, what explains the nonzero E(z)’?
 
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  • #2
You haven't defined K'.
 
  • #3
bcrowell said:
You haven't defined K'.

K' moves in the positive x direction of K at speed v. When the Origin clocks of K and K' coincide, they mutually read zero. The x/x' axes, etc., of the two frames are parallel.
 
  • #4
GRDixon said:
K' moves in the positive x direction of K at speed v. When the Origin clocks of K and K' coincide, they mutually read zero. The x/x' axes, etc., of the two frames are parallel.

Here's a hint: the E' field in K' is the superposition of a conservative part (non-zero divergence) and a non-conservative part (non-zero curl). The non-zero E(z)' on the y' axis at time t'=0 is conservative. The question is, what engenders such a conservative field? The current loop has zero net charge.
 
  • #5
GRDixon said:
Here's a hint: the E' field in K' is the superposition of a conservative part (non-zero divergence) and a non-conservative part (non-zero curl). The non-zero E(z)' on the y' axis at time t'=0 is conservative. The question is, what engenders such a conservative field? The current loop has zero net charge.

The loop's charge density doesn't vanish everywhere, as viewed in K'. For a simpler example, see subsection 4.2.4 of this: http://www.lightandmatter.com/html_books/genrel/ch04/ch04.html#Section4.2 (the situation described in figure b).
 
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  • #6
bcrowell said:
The loop's charge density doesn't vanish everywhere, as viewed in K'. For a simpler example, see subsection 4.2.4 of this: http://www.lightandmatter.com/html_books/genrel/ch04/ch04.html#Section4.2 (the situation described in figure b).

Good eye. In general, uncharged current loops that have an overall component of velocity in the plane of the loop are electrically polarized. It's interesting to model a ceramic, disc-shaped magnet as an array of microscopic uncharged current loops. When the magnet spins, the motion-associated tiny dipoles engender an electric field with a component toward/away from the parent magnet's rotation axis. I have read that even Einstein puzzled over some of the associated "homopolar" effects and their "seats of emf".
 
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FAQ: E Field and Field Transformations

What is an E field?

An E field, or electric field, is a physical quantity that describes the strength and direction of the force experienced by a charged particle in an electric field. It is a vector field, meaning it has both magnitude and direction, and is represented by electric field lines.

How is an E field created?

An E field is created by the presence of electric charges. A positive charge will create an outward electric field, while a negative charge will create an inward electric field. The strength of the E field is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them.

What are the units of an E field?

The SI unit for electric field is Newtons per Coulomb (N/C). However, it can also be expressed in Volts per meter (V/m) or equivalent units.

How do you calculate the electric field at a point in space?

The electric field at a point in space can be calculated using Coulomb's law, which states that the magnitude of the electric field at a point is equal to the force between two charged particles divided by the distance between them squared. This can also be represented mathematically as E = k * (q1 * q2)/r^2, where k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

How do E fields transform when passing through different materials?

When an E field passes through different materials, its strength and direction can change due to the material's dielectric properties. The E field lines will be compressed in denser materials and spread out in less dense materials. The E field can also be reflected, refracted, or absorbed depending on the material's conductivity and permittivity.

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