E field outside a current carrying wire

In summary, the problem in question involves finding the electric field outside a resistanceless wire with steady current. The book claims that there is a 1/r radial field created by a linear charge density, but this assumes a static scenario which is not the case. The field in a wire is typically the gradient of the voltage or proportional to the current density. The question of whether special relativity plays a role and how resistance affects the field is also discussed. The problem is from the 5th edition of HRK's Physics, chapter 38, problem 11. The equivalent passage in the 6th edition can be found online.
  • #1
conquerer7
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Homework Statement



One step in one of the problems in my book (involving calculation of the Poynting vector) asks to find the electric field outside a wire. This wire is resistanceless and the current is steady.

Homework Equations



Maxwell's.

The Attempt at a Solution



Stared at it for a while, had no idea how there would possibly be an electric field, solutions manual says the wire creates a radial one proportional to 1/r.
 
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  • #2
Hmm. This is a strange question. It seems your book is claiming that there is some linear charge density produced by the current, which then that makes a 1/r radial field. However, the linear charge density assumes a static scenario, which you don't have. Really, the way a wire works is that there is some potential across it V=IR, and the field is the gradient of the voltage (or, alternatively, the field is J/resistivity where J is current density).
 
  • #3
Would this have anything to do with special relativity? I remember seeing something about length contraction when switching reference frames once, and about how that produced a charge density out of nowhere.

Edit: what if there's a nonzero resistance?
 
  • #4
which book? :confused:
 
  • #5
5th edition of HRK's Physics, chapter 38, problem 11.
 

FAQ: E field outside a current carrying wire

What is the direction of the electric field outside a current carrying wire?

The electric field outside a current carrying wire is directed radially outward from the wire, in a circular pattern with the wire as the center.

How does the magnitude of the electric field change with distance from the wire?

The magnitude of the electric field decreases with increasing distance from the wire. It follows an inverse relationship, meaning that the farther away from the wire you are, the weaker the electric field will be.

Does the direction of the electric field change with distance from the wire?

No, the direction of the electric field remains the same at all points outside the wire. It is always directed radially outward from the wire.

How does the strength of the current affect the electric field outside a wire?

The strength of the current directly affects the strength of the electric field outside the wire. As the current increases, the electric field also increases.

What factors influence the strength of the electric field outside a current carrying wire?

The strength of the electric field outside a current carrying wire is influenced by the distance from the wire, the strength of the current, and the material properties of the wire. It is also affected by the presence of other nearby objects or sources of electric fields.

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