Easy Identity Question: Proving 2cos(x)sin(x) = sin(2x)

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In summary, The identity is correct and can be found in Wikipedia under double-angle formulas. It is important to use proper notation, such as writing sin(x) or (sin x) instead of sinx, and using parentheses when necessary.
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tmt1
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Hi,

I just want to double check that

2cos(x)sin(x) = 2sin(x)cos(x) = sin(x)2cos(x) = sin(2x)

Thanks,

Tim
 
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Yes. the identity is correct. You can find a list of trigonometric identities in Wikipedia. See, in particular, double-angle formulas.

A couple of remarks about notation. One should write $\sin x$ (with a space) or $\sin(x)$, not sinx. If the argument is followed by another factor, then the argument should be wrapped in parentheses. For example, $\sin x\cos x$ can theoretically be parse either as $\sin(x)\cos(x)$ or as $\sin(x\cos(x))$, but $\sin(x)\cos(x)$ clearly shows that the argument of sine is just $x$.
 

FAQ: Easy Identity Question: Proving 2cos(x)sin(x) = sin(2x)

What is the easiest way to prove 2cos(x)sin(x) = sin(2x)?

The easiest way to prove this identity is by using the double angle formula for sine, which states that sin(2x) = 2sin(x)cos(x). By substituting this into the original equation, we get 2cos(x)sin(x) = 2sin(x)cos(x), which is equivalent and proves the identity.

How can I use the unit circle to prove this identity?

The unit circle can be used to prove this identity by drawing a right triangle within the circle and labeling the sides with the appropriate trigonometric functions. By using the Pythagorean theorem and the fundamental identity cos^2(x) + sin^2(x) = 1, we can manipulate the equation to show that 2cos(x)sin(x) = sin(2x).

Can this identity be proven using algebraic manipulation?

Yes, this identity can be proven using algebraic manipulation. By starting with the left side of the equation and using trigonometric identities such as sin(2x) = 2sin(x)cos(x) and cos(2x) = cos^2(x) - sin^2(x), we can manipulate the equation until it is equivalent to the right side.

Are there any special cases where this identity does not hold true?

Yes, there are a few special cases where this identity does not hold true. One example is when x = 0, where the left side of the equation becomes 0 but the right side is sin(0) = 0. Another example is when x = π/2, where the left side becomes 2cos(π/2)sin(π/2) = 0, but the right side is sin(π) = 0. In these cases, the identity does not hold true because of undefined or indeterminate values.

How can I use this identity in real-world applications?

This identity can be used in real-world applications to simplify and solve trigonometric equations, as well as to evaluate integrals and derivatives involving trigonometric functions. It is also used in various fields such as physics, engineering, and astronomy to model and analyze periodic phenomena. Additionally, understanding this identity can help in proving other more complex trigonometric identities and relationships.

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