- #1
wnvl2
- 49
- 13
Will the presence of attractive interactions between gas molecules raise or lower the molar Gibbs energy of a gas relative to its ‘perfect’ value?
I would think that these attracting forces result in a lower energy state. A decrease in the energy state implies a decrease in the enthalpy. A reduction of the enthalpy implies a lower Gibbs-free energy.
But what will happen to the entropy?
I think that we will get less disorder as the molecules attract each other. And ther will be a little bit more order, even when there is no condensation. For the Gibbs free energy, which is equal to G=H-TS, this means that both effects have to be balanced. So we cannot say in advance what the direction is of the total effect of attractive forces is on the Gibbs-free energy.
Is that reasoning correct?
I would think that these attracting forces result in a lower energy state. A decrease in the energy state implies a decrease in the enthalpy. A reduction of the enthalpy implies a lower Gibbs-free energy.
But what will happen to the entropy?
I think that we will get less disorder as the molecules attract each other. And ther will be a little bit more order, even when there is no condensation. For the Gibbs free energy, which is equal to G=H-TS, this means that both effects have to be balanced. So we cannot say in advance what the direction is of the total effect of attractive forces is on the Gibbs-free energy.
Is that reasoning correct?