- #36
Baluncore
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The 120k has a low duty cycle, it is effective only while the diode is conducting.Tom.G said:This gives a ratio of 56/191 or -0.29 of the B+ voltage. If B+ is 250V then the grid bias is -72.5V, which seemed rather high.
A duty cycle of 25% changes it's effective value in the divider to 120k * 4 = 480k.
Because of the series 120k, the diode current follows the negative sinewave rather than holding the peak negative AC in the capacitor.