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AngelofMusic
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A question about Dynamics and drawing FBDs. In our book, we have an equation that says:
[tex]\Sigma M_O = \Sigma M_{O(effective)}[/tex]
Most of the time, this basically translates into:
[tex]\Sigma M_O = \overline{I}\alpha[/tex]. The left-hand side basically represents the sum of the moments of all the forces on the body and I usually have no trouble coming up with that. It's when the right-hand side includes moments caused by acceleration in addition to Iα where I get confused.
http://img23.photobucket.com/albums/v68/AngelOfMusic/sit1.jpg
In this case, [tex]\Sigma M_{O(effective)} = \overline{I}\alpha + m_Aa_Ar + m_Ba_Br [/tex], where the effective moments include the ones caused by the acceleration of the blocks attached to the pulley.
Is this only the case when the acceleration is due to objects directly connected to the disk?
For example, in the situation here: http://img23.photobucket.com/albums/v68/AngelOfMusic/sit2.jpg , although there is friction between the disk and the cart underneath (rolling without sliding), and the friction causes a centroidal acceleration in the disk in addition to its angular acceleration - the acceleration of the cart does not cause an effective moment in the disk.
The book doesn't quite explain the theory very well, so this is just my hypothesis. When would I have to take into account the acceleration of other objects when calculating the effective moment? Only when the rigid bodies are connected?
Any clarifications or additional explanations would be greatly appreciated!
[tex]\Sigma M_O = \Sigma M_{O(effective)}[/tex]
Most of the time, this basically translates into:
[tex]\Sigma M_O = \overline{I}\alpha[/tex]. The left-hand side basically represents the sum of the moments of all the forces on the body and I usually have no trouble coming up with that. It's when the right-hand side includes moments caused by acceleration in addition to Iα where I get confused.
http://img23.photobucket.com/albums/v68/AngelOfMusic/sit1.jpg
In this case, [tex]\Sigma M_{O(effective)} = \overline{I}\alpha + m_Aa_Ar + m_Ba_Br [/tex], where the effective moments include the ones caused by the acceleration of the blocks attached to the pulley.
Is this only the case when the acceleration is due to objects directly connected to the disk?
For example, in the situation here: http://img23.photobucket.com/albums/v68/AngelOfMusic/sit2.jpg , although there is friction between the disk and the cart underneath (rolling without sliding), and the friction causes a centroidal acceleration in the disk in addition to its angular acceleration - the acceleration of the cart does not cause an effective moment in the disk.
The book doesn't quite explain the theory very well, so this is just my hypothesis. When would I have to take into account the acceleration of other objects when calculating the effective moment? Only when the rigid bodies are connected?
Any clarifications or additional explanations would be greatly appreciated!
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