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Effective Resistance of Circuit: 4.4 Ohm
- Thread starter Icy98
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In summary, the effective resistance of the circuit is 4.4 ohm, as calculated by 1/(1/6 + 1/4)+2 = 4.4 ohm. However, the reason that R3 can be omitted from the circuit is because it is effectively shorted out by the wire forming the corner, resulting in almost no current flowing through it. This was determined through the help of other users on the forum.
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andrevdh
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diagram/circuit?
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Icy98
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Thank you. I've just uploaded the picture.andrevdh said:
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stockzahn
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- #5
Icy98
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Is this correct?
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andrevdh
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It is "shorted out" by the wire forming the corner, so there is in effect "no resitance" due to the wire. That means that you can redraw the circuit without the R3 resistor.
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stockzahn
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Icy98 said:
You missed something. There is another cable/connection from point A to the other and of R3.
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andrevdh
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Think of electric current flowing like water from the + terminal towards the - terminal of the battery.
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Icy98
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What is the reason that we can omit R3?
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stockzahn
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Icy98 said:
Complete the drawing from your 3rd post with the missing cable/connection. Then you will see.
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BvU
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Good thread ! You really adapted quickly to the PF cultureIcy98 said:
!In the upper right of the original picture, there is a ' 0 ##\Omega## resistor ' in parallel with the 2 ##\Omega## resistor. Does that help ?
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Icy98
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Is this correct?
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stockzahn
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Icy98 said:
Looks good, well done!
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Icy98
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Thanks a lot to stockzahn, andrevdh and BvU for helping![emoji16][emoji5]️
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andrevdh
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It's a pleasure. The potential difference over a small resistor, or in this case the corner wire, is almost zero. That means that the potential difference over the R3 resistor is also almost zero so that almost no current flows through it. It is thus not contributing to the circuit and can be ignored or eliminated.
FAQ: Effective Resistance of Circuit: 4.4 Ohm
What is the formula for calculating the effective resistance of a circuit?
The formula for calculating the effective resistance of a circuit is R = R1 + R2 + R3 + ... + Rn, where R represents the total resistance and R1, R2, R3, and so on represent the individual resistances in the circuit.
How do you determine the effective resistance of a series circuit?
In a series circuit, the effective resistance is simply the sum of all the individual resistances in the circuit. This can be calculated using the formula R = R1 + R2 + R3 + ... + Rn.
What is the effective resistance of a parallel circuit?
In a parallel circuit, the effective resistance is calculated using the formula 1/R = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn. To find the effective resistance, you would take the reciprocal of this sum.
How does adding resistors in series affect the effective resistance?
Adding resistors in series increases the effective resistance of the circuit. This is because the total resistance is the sum of all the individual resistances, and adding more resistors will increase that sum.
How does adding resistors in parallel affect the effective resistance?
Adding resistors in parallel decreases the effective resistance of the circuit. This is because the formula for calculating the effective resistance in a parallel circuit involves taking the reciprocal of the sum of the reciprocals of the individual resistances. Adding more resistors in parallel will decrease the overall value of this sum, resulting in a lower effective resistance.