Effective Spring Constant of Springs in Series: Deriving & Explaining

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The effective spring constant for two springs in series is derived using the formula k_eff = k1k2/(k1+k2). The force exerted on each spring remains constant due to Newton's third law, which states that the force exerted by one spring on another is equal and opposite. This means that the force acting on both springs is the same, allowing for the derivation of the effective spring constant. Understanding this relationship is key to solving problems involving springs in series. The discussion emphasizes the importance of Newton's laws in explaining the behavior of the system.
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Homework Statement


I am trying to derive the effective spring constant of two springs, with different spring constants, in series. I know the equation is everyone online, so the effective spring constant is k1k2/k1+k2.

So the question is, when deriving it, the force exerted on each spring is constant, why is that?? :confused:

Homework Equations


Hooke's Law -> Fx = kx

The Attempt at a Solution


Is it because of Newton's third law? If so, how does that work?? Force of mass on spring 2 is equal to force of spring 2 on spring 1? So the force acting on each spring is Fg??:confused:
 
Last edited:
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Hi Morass! :smile:
Morass said:
… Is it because of Newton's third law? If so, how does that work?? Force of mass on spring 2 is equal to force of spring 2 on spring 1?

Yes.
 

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