- #1
onako
- 86
- 0
After the eigendecomposition of the following matrix is performed, I wonder what happens to the eigenvectors and eigenvalues of the matrix obtained by flipping rows of the original. Say the original is
0 5 7 8
5 0 2 9
7 2 0 3
8 9 3 0
and the flipped version is:
5 0 2 9
8 9 3 0
7 2 0 3
0 5 7 8
Using the online matrix calculator says (at first glance) that the eigendecomposition data of the original and flipped version have no relation. But, SVD of the original and the flipped appear to be related: right singular vectors and singular values of the original and flipped are the same, and they are equal to the eigenvectors and eigenvalues of the original. (left singular vectors of flipped matrix are also flipped). I would like to hear the reasoning behind this behaviour.
More precisely, what is the relation between the eigendecomposition of the original and the flipped version, and how might this be related to the svd.
Thanks
0 5 7 8
5 0 2 9
7 2 0 3
8 9 3 0
and the flipped version is:
5 0 2 9
8 9 3 0
7 2 0 3
0 5 7 8
Using the online matrix calculator says (at first glance) that the eigendecomposition data of the original and flipped version have no relation. But, SVD of the original and the flipped appear to be related: right singular vectors and singular values of the original and flipped are the same, and they are equal to the eigenvectors and eigenvalues of the original. (left singular vectors of flipped matrix are also flipped). I would like to hear the reasoning behind this behaviour.
More precisely, what is the relation between the eigendecomposition of the original and the flipped version, and how might this be related to the svd.
Thanks