- #1
JinM
- 66
- 0
Is this a correct realization? The eigenspaces corresponding to the eigenvalues of A are the same as the eigenspaces corresponding to the eigenvalues of A^-1, transpose of A, and A^k for any k > 1.
It took me some time to realize this but the v's, when you manipulate these equations, don't change. So I'm lead to believe that the eigenvectors are actually the same for all such variants of A.
It took me some time to realize this but the v's, when you manipulate these equations, don't change. So I'm lead to believe that the eigenvectors are actually the same for all such variants of A.