Einstein's Definition of Mass: m = E/c^2

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Einstein's equation E=mc^2, which can be rearranged to m=E/c^2, illustrates the equivalence of mass and energy in special relativity. This relationship indicates that mass can be defined in terms of energy, emphasizing that rest energy and mass are fundamentally linked. When a body emits energy E, its mass decreases by E/c^2, demonstrating how energy loss affects mass. The discussion clarifies that both forms of the equation are used interchangeably by Einstein. Understanding this equivalence is crucial for grasping the principles of mass-energy conversion in physics.
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Greetings: I hope I am posting in the appropriate forum. I understand that in special relativity, Einstein expressed e = mc^2 as m = e/c^2. Is this his way of defining mass? If not, can you explain how he came to this conclusion?
 
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I am not sure if I understand your question. ##E=mc^2## is the same as ##m=E/c^2##. Are you confused about that equivalence or are you asking for a derivation of it?
 
Are you referring to a specific paper in which the equation in the form ##m=E/c^2## appears? If so, please cite the paper so we understand the context. Otherwise, I'm sure Einstein used the equation in both forms regularly.
 
nikkor180 said:
Is this his way of defining mass?

No, rest energy and mass are equivalent. That's what he's saying.

If not, can you explain how he came to this conclusion?

He showed that if a body gave off an amount of energy ##E## its mass would be reduced by ##E/c^2##.
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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