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22flakes
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Homework Statement
A .1 m ramp is sitting at the edge of a horizontal surface that is 1 m from the ground. One ball is resting at the top of a ramp and another ball is resting at the bottom of the ramp where it is flattened. Each ball has a mass of .05 kg. Ball one is released and hits ball two. Find the displacement of ball two and the angle that it makes relative to the starting position. The starting position is at angle 0 degrees.
Homework Equations
When VB, i=0
VA, f = [(mA - mB)/(mA + mB)]VA, i
VB, f = [2ma/(mA + mB)]Va, i
R=[(Vi^2sin2(theta))/g]
y= Viy - gt
The Attempt at a Solution
I know that I have to find the VA in order to get VB, but if I try to solve for those velocities, I end up with 0. VA, i is 0, and when plugged in it gives the final velocities at 0. I thought about trying to use the variables and cancel out somehow, but that didn't lead me anywhere.
I know that when the balls are both in free fall they'll have a constant velocity because of gravity, but time isn't given. I also tried to figure out a way to find t through other equations and plug it in, but I couldn't find a way.
I also don't know how to find the final angle.
I appreciate all help.