Elastic potential energy of vertical spring

In summary, we discussed several problems involving springs and their force constants, work required to compress or stretch the springs, and maximum acceleration experienced by objects attached to the springs. We also determined the stiffness of two different springs based on the amount of work required to compress or stretch them.
  • #1
Vanessa22
2
0
help is urgently needed please and thank u.

1. When a 13.2-kg mass is placed on top of a vertical spring, the spring compresses 5.93 cm. Find the force constant of the spring.

2. If a spring has a spring constant of 400 N/m, how much work is required to compress the spring 25.0 cm from its undisturbed position?

3. A compressed spring that obeys Hooke's law has a potential energy of 18 J. If the spring constant of the spring is 400 N/m, find the distance by which the spring is compressed.

4. An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The string stretches by 0.165 m. The spring is then cut into two identical springs of 50 coils each. Each spring is attached between the ceiling and the object. By how much does each spring stretch?

5. A vertical spring stretches 10 cm under a load of 200 g.
a. Determine the spring constant.
b. How much work is required to stretch the first 5 cm.
c. How much work is required to stretch the last 5 cm.

6. A mass sitting on a horizontal frictionless surface is attached to one end of spring; the other end of the spring is fixed to a wall. To compress the spring by 0.12 m requires 3.0 J of work. If the mass is released from rest with the spring compressed, it experiences a maximum acceleration of 15 m/s/s. Find the value of the spring constant.

7. To compress spring 1 by 0.20 m takes 150 J of work. Stretching spring 2 by 0.30 m requires 210 J of work. Which spring is stiffer?
 
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  • #2
Hi Venessa, Welcome to PF

1) we need to see your work using the homework template
2) we need to see each problem in it own thread otherwise you'll get a tangled mess of intertwining comments
3) We can't help you if you don't show your work

-source: jedishrfu:smile:
 
  • #3
4.An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The string stretches by 0.165 m. The spring is then cut into two identical springs of 50 coils each. Each spring is attached between the ceiling and the object. By how much does each spring stretch?
- x= 1/2x100/0.165
=50/0.165
=303.03m

6. A mass sitting on a horizontal frictionless surface is attached to one end of spring; the other end of the spring is fixed to a wall. To compress the spring by 0.12 m requires 3.0 J of work. If the mass is released from rest with the spring compressed, it experiences a maximum acceleration of 15 m/s/s. Find the value of the spring constant.
- k=f/x
=3/0.12
=25 n/m

7.To compress spring 1 by 0.20 m takes 150 J of work. Stretching spring 2 by 0.30 m requires 210 J of work. Which spring is stiffer?
-
a. k=f/x
=150/0.20
=750 n/m

b. k=f/x
=210/0.30
=700 n/m
~so the stiffer spring would be spring number 2
 

Related to Elastic potential energy of vertical spring

1. What is elastic potential energy?

Elastic potential energy is the energy stored in an object or system due to its deformation or change in shape. It is a type of potential energy that arises from the elastic properties of materials, such as springs.

2. How is elastic potential energy of a vertical spring calculated?

The elastic potential energy of a vertical spring can be calculated using the formula E = 1/2kx^2, where E is the elastic potential energy, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

3. What factors affect the elastic potential energy of a vertical spring?

The elastic potential energy of a vertical spring is affected by its spring constant, displacement, and mass. A stiffer spring with a higher spring constant will have a greater elastic potential energy for the same displacement. Similarly, a larger displacement or a heavier mass attached to the spring will also increase its elastic potential energy.

4. How does the elastic potential energy of a vertical spring change with displacement?

The elastic potential energy of a vertical spring is directly proportional to the square of its displacement from the equilibrium position. This means that as the displacement increases, the elastic potential energy also increases, and vice versa.

5. What is the relationship between elastic potential energy and kinetic energy in a vertical spring system?

In a vertical spring system, elastic potential energy is converted into kinetic energy as the object attached to the spring moves up and down. At the equilibrium position, all the potential energy is converted into kinetic energy, and at the maximum displacement, all the kinetic energy is converted back into potential energy.

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