- #1
Rasine
- 208
- 0
Three charges, Q1, Q2, and Q3 are located in a straight line. The position of Q2 is 0.279 m to the right of Q1. Q3 is located 0.180 m to the right of Q2. In the above problem, Q1 = 1.90 × 10-6 C, Q2 = -2.65 × 10-6 C, and Q3 = 3.18 × 10-6 C. Calculate the total force on Q2. Use a plus sign for a force directed to the right.
ok so first i try to calcuate the force of 1 on 2
so i use the equation f=(kq1q2)/r^2 ...so that would be
=(8.99E9*1.90E-6*-2.65E-6)/.279^2 = -.58150
or should i take the net electric charge and then calcuate the force of that charge at the point .279 away from q1?
(continue with first approch) then i calcuate the foce of 3 on 2
=(8.99E9*3.18E-6*-2.65E-6)/.180^2= -2.338
then i sum all the forces acting on 2 and i get -2.92 whic does not make sense.
what am i doing wrong
ok so first i try to calcuate the force of 1 on 2
so i use the equation f=(kq1q2)/r^2 ...so that would be
=(8.99E9*1.90E-6*-2.65E-6)/.279^2 = -.58150
or should i take the net electric charge and then calcuate the force of that charge at the point .279 away from q1?
(continue with first approch) then i calcuate the foce of 3 on 2
=(8.99E9*3.18E-6*-2.65E-6)/.180^2= -2.338
then i sum all the forces acting on 2 and i get -2.92 whic does not make sense.
what am i doing wrong