Electric Circuit. Norton Equivalent current

In summary, the conversation revolves around finding the Norton and Thevenin equivalents of an electric circuit and solving related problems. Some methods were attempted, but were found to be incorrect. Eventually, the correct solutions were found with the help of source transformations and other techniques. One of the problems involved finding the Thevenin voltage, which was equal to the open-circuit voltage of 36000 V. Another problem involved determining Vth using a dependent source and finding Rth using a test source. With the help of others, the correct answers were eventually obtained.
  • #1
Hitman6267
17
0
Electric Circuit. Norton/Thevelin Equivalents

Unsolved Problem
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I used a node voltage equation to try and get Vth and the I in the short-circuit to get the Rth but it didn't work.

Unsolved Problem
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I used a node voltage equation to get Vth and I in the short-circuit. Got Rth and used in the in Vth^2 / 4 RL (with RL = Rth)

My answer was wrong. Is the method correct ?


Solved this my self
Removed to make space for another problem

For me, I find that the Norton equivalent is going to be 12A since the independent current source forces that ampage. But apparently I'm wrong. (I get feedback from a web form when I submit the answer). Any one can tell me what's wrong with my thought process ? Thank you.

Solution:
After doing a source transformation and adding up the resistors. You can get the correct the Norton current value.

Solved
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I thought that if I did a source transformation getting a 36000V source would solve the problem because there isn't any other voltage source in the circuit. I was wrong. Any hints on this one ?
 
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  • #2


Hitman6267 said:
Unsolved Problem
View attachment 24900

I thought that if I did a source transformation getting a 36000V source would solve the problem because there isn't any other voltage source in the circuit. I was wrong. Any hints on this one ?
You're right. The Thevenin voltage is the open-circuit voltage, which is 36000 V.
 
  • #3
Yes it turns out my answer is correct and that they forgot to ask for the answer in kilo ohm.

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Can anyone tell me why the the Vth is equal to the v in the dependent source "3V"

A solution says i = [tex]\frac{5-3V}{2000}[/tex] = [tex]\frac{5-3Vth}{2000}[/tex]
 

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  • #4
Think about how you usually determine Vth.
 
  • #5
I'm going to ask my professor about that problem. Thank you though. Could you have a look at the first problem in my first post ?

I'm pretty sure I need to find Rth using a test source but I can't seem to do it right. (A web form tells me my answer is wrong)

What I tried, I added a current source of 5A to node A. And deactivated the 12V source. The next step for me is to find Vx so I can add it up with R2 * 5A and get Vth. In the end I'll get Rth from, Vth/Ith. But I have failed to get a right answer.Edit: got help with solving it. thank you :)
 
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FAQ: Electric Circuit. Norton Equivalent current

1. What is an electric circuit?

An electric circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery, and various components, such as resistors, capacitors, and inductors, connected by conductive wires.

2. What is Norton Equivalent current?

Norton Equivalent current is a theoretical concept used to simplify the analysis of complex electrical circuits. It represents the current that would flow through a short circuit across the output terminals of a circuit if all the internal components were replaced by an equivalent current source.

3. How is Norton Equivalent current calculated?

Norton Equivalent current can be calculated by determining the total resistance of the circuit, also known as the equivalent resistance. This can be done by combining resistors in series and parallel, and then dividing the voltage across the circuit by the total resistance. The resulting value is the Norton Equivalent current.

4. What is the difference between Norton Equivalent current and Thevenin Equivalent current?

The main difference between Norton Equivalent current and Thevenin Equivalent current is the type of equivalent source used. Norton Equivalent uses a current source, while Thevenin Equivalent uses a voltage source. Additionally, Norton Equivalent is calculated by shorting the output terminals, while Thevenin Equivalent is calculated by open-circuiting the output terminals.

5. Why is Norton Equivalent current useful?

Norton Equivalent current is useful because it allows for the simplification of complex circuits, making them easier to analyze and understand. It also allows for the calculation of the maximum current that can be drawn from a circuit without affecting its operation, which is important for designing and troubleshooting electrical systems.

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