Electric Field due to a Ring of Charge

In summary, the conversation is about a problem involving finding the maximum electric field due to a ring of uniform charge. The equation for this problem is given, but the person is struggling to find the correct approach and is asking for help. Eventually, they confirm that their approach was correct and they were able to solve the problem, but with some difficulty due to their algebra skills. There is also a mention of not knowing how to deal with having two unknowns in the equation.
  • #1
DarkWarrior
5
0
I've been stuck on this problem for awhile now..

At what distance along the central axis of a ring of radius R and uniform charge is the magnitude of the electric field due to the ring's charge maximum?

Now, I know that the equation for this problem is E = [k|qz|] / [(z^2+R^2)^3/2], which is the electric field magnitude of a charged ring. And to get the maximum, you have to find where the first derivative of the equation where it equals zero.

But when I take the derivative of the equation, I get a complete mess not even close to the answer. Can anyone give me some hints or a push in the right direction? Is my thinking incorrect? Thanks. :)
 
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  • #2
It's a straighforward problem, and your approcah is right. If you could just post your work, we can try to help you out.
 
  • #3
Thanks, confirming that I was going in the right direction was all I needed. I eventually did get the answer, but with some difficultly thanks to my poor algebra skills. :)
 
  • #4
In this problem we do not know E and we are looking for z correct? I do not know how to deal with this problem of having two unknowns. I am given R but that is all.
 
  • #5


Hi there,

It seems like you are on the right track with finding the maximum electric field due to a ring of charge. However, it is important to remember that the electric field is a vector quantity, so the magnitude alone may not give you the full picture.

To find the maximum electric field, you can use the equation E = [k|qz|] / [(z^2+R^2)^3/2] and take the derivative with respect to z. This will give you a function for the derivative of the electric field with respect to z.

Next, set this derivative equal to zero and solve for z. This will give you the location along the central axis where the electric field is maximum. You can then plug this value of z back into the original equation to find the maximum electric field magnitude.

If you are still having trouble, it may be helpful to review the concept of taking derivatives and solving for maximum or minimum values. You can also try using an online graphing calculator to plot the derivative function and visually see where it crosses the x-axis, indicating a maximum or minimum point.

I hope this helps and good luck with your problem!
 

FAQ: Electric Field due to a Ring of Charge

1. What is an electric field and how is it affected by a ring of charge?

An electric field is a physical quantity that describes the force experienced by a charged particle in the presence of other charged particles. The strength and direction of an electric field is affected by the magnitude and distribution of the charges in its surroundings, including a ring of charge.

2. How is the electric field calculated for a ring of charge?

The electric field due to a ring of charge can be calculated using the formula E = kqz/((z^2 + R^2)^3/2), where k is the Coulomb constant, q is the charge on the ring, z is the distance from the center of the ring, and R is the radius of the ring.

3. What is the direction of the electric field for a ring of charge?

The electric field for a ring of charge is directed perpendicular to the plane of the ring, pointing away from the ring on one side and towards the ring on the other side. This direction can be determined using the right-hand rule, with the fingers pointing in the direction of the current flow and the thumb pointing in the direction of the electric field.

4. How does the electric field change as the distance from the ring of charge increases?

The strength of the electric field due to a ring of charge decreases as the distance from the ring increases. This is because the electric field follows an inverse-square law, meaning that it decreases proportionally to the square of the distance from the source.

5. Can the electric field due to a ring of charge be negative?

Yes, the electric field due to a ring of charge can be negative. This indicates that the direction of the electric field is opposite to the direction of the positive charges on the ring. The sign of the electric field is dependent on the sign and distribution of charges in the surroundings.

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