- #1
Demon117
- 165
- 1
Suppose that you have a sheet of copper that carries a surface charge of [itex]\sigma[/itex] on each face. The electric field just outside of each face can be calculated by plane symmetry and the solution would take the form
[itex]E=\frac{\sigma}{2\epsilon_{0}}\hat{n}[/itex]
correct?
If not I have to go back and rework this. Also, wouldn't the electric field inside the sheet be zero? The reason would be that the electric flux through the surface is zero.
[itex]E=\frac{\sigma}{2\epsilon_{0}}\hat{n}[/itex]
correct?
If not I have to go back and rework this. Also, wouldn't the electric field inside the sheet be zero? The reason would be that the electric flux through the surface is zero.
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