- #1
Moara
- 43
- 5
- Homework Statement
- The electric field in point A due to the cube with side a and with uniform volumetric charge density is E. What is the electric field at point A when a cube of side a/2 is taken out from the original cube, such as in the picture.
- Relevant Equations
- E=kq/r^2
Tried to use gauss law but there isn't any usefull symmetry that I have seen. Also tried to integrate the field due to small charges over the whole cube, didn't work too since the integral were too much complicated.