- #1
Bashyboy
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Homework Statement
A rod 16.0 cm long is uniformly charged and has a total charge of -21.0 µC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center.
Homework Equations
The Attempt at a Solution
The equation I am advised to use is, [itex]\vec{E}=k_e\frac{\lambda l}{d(l+d)}[/itex], which becomes [itex]\vec{E}=k_e\frac{q}{d(l+d)}[/itex]. I understand how the numerator is formed, but how the author comes up with the numerator is something I am a little confused about. Could some possible explain how this formula is developed and what precisely it means?