Electric field of wire and cylinder at one point in space

In summary, you need to break the fields into components, and then add the vectors representing the fields as superpositions.
  • #1
uni98
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Homework Statement
Given a cylinder of radius R with volumetric charge density, whose axis coincides with the z axis and a uniformly charged infinite wire that coincides with the y axis. Calculate the force felt by a point charge q placed at point A (R / 3, R / 3, R).
Relevant Equations
Cylinder field inside: ρR^2/2rε

Cylinder field outside: ρr/2ε

Field generated by the wire: λ/2πr
I can calculate the fields generated by the cylinder and the wire but I don't know how to calculate their vector sum to evaluate it at point A.
Cylinder field inside: ρR^2/2rε
Cylinder field outside: ρr/2ε
Field generated by the wire: λ/2πr
I should break the fields into components but I don't know how to proceed. Even if you know some sites on which I can find information about it, that's fine. I hope for your help, I really need it. Thank you in advance.
 
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  • #2
uni98 said:
I should break the fields into components but I don't know how to proceed.
Make a drawing with x, y and z axes. Then draw point A. You know the magnitude of the field at A due to the wire alone. Draw an arrow representing that field. In what direction is that arrow?

Once you have that, draw a second arrow at A due to the cylinder alone. In what direction is that? Add the arrows as vectors.

If you get stuck, be sure to post what you have done.
 
  • #3
kuruman said:
Make a drawing with x, y and z axes. Then draw point A. You know the magnitude of the field at A due to the wire alone. Draw an arrow representing that field. In what direction is that arrow?
In the meantime, excuse me if the drawing is not very clear. I represented the thread with the purple color and point A is green. I have represented the vector of the electric field generated by the wire towards point A and its components which are along the z and x axis.
filo.png
kuruman said:
Once you have that, draw a second arrow at A due to the cylinder alone. In what direction is that? Add the arrows as vectors.
I proceeded in the same way with the cylinder and I represented the components of the electric field towards A, the components are along the x and y axis.

cilindro.png


At this point, I'm probably missing some basic trigonometry concepts that I should review. I should break down each of the electric field vectors into their x, y, z components. If you could tell me how you would break them down, I can try to guess the logic.
 
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  • #4
You might have to see this
https://en.wikipedia.org/wiki/Vecto...cal_coordinates#Cylindrical_coordinate_system

in order to check how to convert between the components of cylindrical coordinates ##E_r,E_{\phi},E_z## and the components of cartesian coordinates ##E_x,E_y,E_z## (ok it is obvious that the ##E_z## components are the same).

Extra caution is needed when you will convert the electric field from the infinite wire because there the y-axis is essentially the z-axis of its cylindrical coordinate system so the roles of y and z get swapped.

Once you have the fields in the cartesian components of the common cartesian coordinate system, then it is a straightforward task to add them, you just add them component wise,i.e. ##E_x+E'_x## for the x-component of the total E-field, (where ##E_x## the x-component of the field from the cylinder and ##E'_x## the x-component of the field from the wire).
 
  • #5
In order to help a bit more the link I gave you is about how to convert between the coordinates , and how to convert between the unit vectors. If you understand the conversion of the unit vectors then it is a straightforward task to convert between the components.
For example if
$$\hat r=\cos\phi\hat x+\sin\phi\hat y$$ then the it would be $$E_r\hat r=E_r\cos\phi\hat x+E_r\sin\phi\hat y$$ so it would be $$E_x=E_r\cos\phi+...$$ and $$E_y=E_r\sin\phi+...$$ where i put +... because there is additional contribution from the ##E_{\phi}## component but ok this component is actually zero in this problem
 
  • #6
uni98 said:
I proceeded in the same way with the cylinder and I represented the components of the electric field towards A, the components are along the x and y axis.
You will not get very far unless your drawing is correct and you have a correct conceptual understanding of what's going on.

If you want to find the superposition of two fields, one from the wire and one from the cylinder, at point A, you need to represent them as two arrows both of which have their tails at point A. That's what you need to add.

First make a drawing in the xz plane. Draw a dot for the wire coming out of the screen. Add point A. Draw the single arrow for the field due to the wire. Define some angle relative to the z-axis and find the components. Remember SOH-CAH-TOA. The electric field is the hypotenuse. Do that first and then we'll worry about the cylinder.

On edit: You need to swap the labels for what's inside and what's outside for the fields due to the cylinder. Also, your expression for the field due to the wire needs a factor of ε0 in the denominator.
 
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FAQ: Electric field of wire and cylinder at one point in space

What is the electric field of a wire at a point in space?

The electric field of a wire at a point in space is the force per unit charge that a test charge would experience if placed at that point. It is a vector quantity, meaning it has both magnitude and direction, and is typically measured in units of newtons per coulomb (N/C).

How is the electric field of a wire calculated?

The electric field of a wire can be calculated using Coulomb's law, which states that the magnitude of the electric field is directly proportional to the magnitude of the charge on the wire and inversely proportional to the square of the distance from the wire. The direction of the electric field can be determined by the direction of the force that a positive test charge would experience at that point.

What factors affect the electric field of a wire?

The electric field of a wire is affected by several factors, including the magnitude of the charge on the wire, the distance from the wire, and the medium through which the electric field is passing. Additionally, the shape and orientation of the wire can also impact the electric field at a given point in space.

What is the electric field of a cylinder at a point in space?

The electric field of a cylinder at a point in space is the same as the electric field of a wire at that point, as long as the cylinder is infinitely long and has a uniform charge distribution. This is because the electric field created by a cylinder is essentially the same as the electric field created by a long, thin wire.

How does the electric field of a cylinder compare to that of a wire?

The electric field of a cylinder is similar to that of a wire, but it may have a slightly different shape due to the cylindrical geometry. However, as the distance from the cylinder increases, the electric field behaves similarly to that of a wire, decreasing in strength according to the inverse square law.

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