- #1
DrBanana
- 47
- 3
##\vec{E}## on the line that perpendicularly bisects the segment that joins two equal and opposite charges is non-zero, as it should be. But the potential of any point along that line is zero. But we know know that ##E=-\frac{dV}{dr} ##, where V is approximately ##\frac{1}{4\pi \epsilon} \frac{pcos\theta}{r}## (if the charges are close together) where p is the magnitude of the dipole moment . If I differentiate that with respect to r and set ##\theta=\frac{\pi}{2}##, I still get E=0. What gives?