Electric Field & Potential Inside a Charged Sphere

In summary, the electric field inside a hollow, uniformly charged sphere is zero. This does not necessarily mean that the potential is also zero inside the sphere. The potential at infinity is usually taken to be zero, so to find the potential inside the sphere, one could use the known values of the electric field and potential at infinity. This approach can help determine the potential inside the sphere. However, for homework problems, it is important to show your own work and thinking process.
  • #1
Rashid101
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The electric field inside a hollow, uniformly charged sphere is zero. Does this imply that the potential is zero inside the sphere? Explain.
 
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  • #2
Rashid101 said:
The electric field inside a hollow, uniformly charged sphere is zero. Does this imply that the potential is zero inside the sphere? Explain.

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While you can often find help and advice on this forum, you won't find homework solutions. We'll help you help yourself, but you need to show your work / thinking on homework problems.

As a hint, what is the electric field (inside the shell, and outside), and what is the potential at infinity? With these in mind, how might you approach the potential?
 
  • #3


Yes, the fact that the electric field is zero inside a hollow, uniformly charged sphere does imply that the potential is also zero inside the sphere. This is because the electric field and potential are directly related and can be mathematically described by the equation E = -∇V, where E is the electric field, V is the potential, and ∇ is the gradient operator. This equation shows that when the electric field is zero, the potential must also be zero.

In the case of a hollow, uniformly charged sphere, the electric field is zero inside the sphere because the electric charges on the surface of the sphere are uniformly distributed and cancel each other out. This means that there are no electric field lines pointing inwards towards the center of the sphere, resulting in a net electric field of zero inside the sphere.

Since the electric field is zero inside the sphere, the potential must also be zero according to the equation E = -∇V. This means that there is no change in electric potential as one moves inside the sphere, and therefore the potential is constant and equal to zero throughout the interior of the sphere.

In summary, the fact that the electric field is zero inside a hollow, uniformly charged sphere implies that the potential is also zero inside the sphere due to the mathematical relationship between the two quantities.
 

FAQ: Electric Field & Potential Inside a Charged Sphere

What is an electric field?

An electric field is a physical quantity that describes the influence of electric forces on a charged particle. It is a vector quantity that has both magnitude and direction and is created by electric charges.

How is the electric field calculated inside a charged sphere?

The electric field inside a charged sphere is calculated using the formula E = kQr/R^3, where E is the magnitude of the electric field, k is the Coulomb's constant, Q is the charge of the sphere, r is the distance from the center of the sphere, and R is the radius of the sphere.

Does the electric field inside a charged sphere change with distance from the center?

Yes, the electric field inside a charged sphere decreases as the distance from the center increases. This is because the electric field is inversely proportional to the square of the distance from the center, according to the formula E = kQr/R^3.

What is the potential inside a charged sphere?

The potential inside a charged sphere is the electric potential energy per unit charge at a given point inside the sphere. It is calculated using the formula V = kQ/R, where V is the potential, k is the Coulomb's constant, Q is the charge of the sphere, and R is the distance from the center of the sphere.

How does the potential inside a charged sphere vary with distance from the center?

The potential inside a charged sphere decreases as the distance from the center increases. This is because the potential is directly proportional to the distance from the center, according to the formula V = kQ/R. As the distance increases, the potential decreases, indicating a decrease in the electric field strength.

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