- #1
Buffu
- 849
- 146
Homework Statement
Solve by integration method :-
From a spherical shell of radius ##a##, a circular disk of radius ##b## has been removed. The shell has a surface charge density ##\sigma##. Find the Electric field through that aperture.
Homework Equations
The Attempt at a Solution
We put the midpoint of the aperture at the origin.
Then I got,
##\displaystyle E = \int_\text{Region} {\sigma dA \over (R(A))^2}##.
Where is ##R## is function that depends on area to output the distance between the small charge and the origin.
The problem is that I am unable to express ##R## in terms of ##A##.After thinking for a lot of time I have not done much,
Any hints on how to move from here ?