- #1
Young_Scientist23
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- TL;DR Summary
- Derivation of equation which correlate electric fields of coupled lines with coupling. The question is: what will happen with electric field between line and ground plane in scenario, where coupling is strong.
Hello All,
I'm trying to create equation which can describe relation between electric fields of three coupled-lines and coupling between them. Let we say that, we have thee lines having infinit length which are placed above ground plane in distance h. The distance between coupled lines is marked as [l]d[/l]. Each line has defined electric potential (e.g. line no. 1 has potential ##V_{1}## and so on). Now what I'm trying to do. I'm trying to create equation which can correlate mutual capacitances (##C_{12}##, ##C_{23}##) between the lines, with their electric fields (existing between the lines and ground plane - ##\vec{E_{1}}\\##, ##\vec{E_{2}}##, ##\vec{E_{3}}##). It is quite intuitive that, when you decrease distance between the lines, the electric field around middle line no. 2 will be more "concentrated" between the lines nor the ground plane. Moreover, I'm observing it in some simulations and capacitance matrices. I'm just wondering how to proof that mathematically.
I take Laplace to start solving this case, however I'm not quite sure whether it is good way to solve the issue. For this case I derive folowing equations:
$$\frac{d^2V_{1}(x)}{dx^2} - C_{12}\frac{d^2V_{2}(x)}{dx^2} = 0$$, $$\frac{d^2V_{2}(x)}{dx^2} - C_{12}\frac{d^2V_{1}(x)}{dx^2} - C_{23}\frac{d^2V_{3}(x)}{dx^2} = 0$$, $$\frac{d^2V_{3}(x)}{dx^2} - C_{23}\frac{d^2V_{2}(x)}{dx^2} = 0$$.
When I'm trying to solve the second equation in terms of distribution of electric fields and mutual capacitances, I'm "landing" in this equation:
$$\vec{E_{2}} = (\vec{E_{1}} + \vec{E_{3}})C_{mut} $$
where ##C_{mut} = C_{12} = C_{23}##.
Assuming that the electric fields of lines no. 1 and no. 3 are constant, the electric field ##\vec{E_{2}}## of line no. 2 decrease only, when distance between lines is increasing, what has no sense. What I'm doing wrong ? Could someone come up with the correct thought ?
Best Regards,
Tom
I'm trying to create equation which can describe relation between electric fields of three coupled-lines and coupling between them. Let we say that, we have thee lines having infinit length which are placed above ground plane in distance h. The distance between coupled lines is marked as [l]d[/l]. Each line has defined electric potential (e.g. line no. 1 has potential ##V_{1}## and so on). Now what I'm trying to do. I'm trying to create equation which can correlate mutual capacitances (##C_{12}##, ##C_{23}##) between the lines, with their electric fields (existing between the lines and ground plane - ##\vec{E_{1}}\\##, ##\vec{E_{2}}##, ##\vec{E_{3}}##). It is quite intuitive that, when you decrease distance between the lines, the electric field around middle line no. 2 will be more "concentrated" between the lines nor the ground plane. Moreover, I'm observing it in some simulations and capacitance matrices. I'm just wondering how to proof that mathematically.
I take Laplace to start solving this case, however I'm not quite sure whether it is good way to solve the issue. For this case I derive folowing equations:
$$\frac{d^2V_{1}(x)}{dx^2} - C_{12}\frac{d^2V_{2}(x)}{dx^2} = 0$$, $$\frac{d^2V_{2}(x)}{dx^2} - C_{12}\frac{d^2V_{1}(x)}{dx^2} - C_{23}\frac{d^2V_{3}(x)}{dx^2} = 0$$, $$\frac{d^2V_{3}(x)}{dx^2} - C_{23}\frac{d^2V_{2}(x)}{dx^2} = 0$$.
When I'm trying to solve the second equation in terms of distribution of electric fields and mutual capacitances, I'm "landing" in this equation:
$$\vec{E_{2}} = (\vec{E_{1}} + \vec{E_{3}})C_{mut} $$
where ##C_{mut} = C_{12} = C_{23}##.
Assuming that the electric fields of lines no. 1 and no. 3 are constant, the electric field ##\vec{E_{2}}## of line no. 2 decrease only, when distance between lines is increasing, what has no sense. What I'm doing wrong ? Could someone come up with the correct thought ?
Best Regards,
Tom