Electric fields and electric potential

In summary: Va = Q/4piEoR - (Qra^2/4piEor^3) + 2Q/8piEoRand since rb=R, Va = Q/4piEoR - (Qra^2/2piEor^3) = Q/2piEoRand the electron will hit the lower plate, since Va is positive(b) If the electron does not strike one of the plates, then where will it be at the end of its path?Since the electron is moving and has momentum, it will end up at some point between the two plates. You would have to find the distance and time
  • #1
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I've been doing some questions and I'm completely stuck on three of them. I tried thinking of how to tackle them but I'm coming up blank.

1. A charge of q is distributed uniformly throughout a spherical volume of radius R. Setting V = 0 at infinity, show the potential at a distance r from the center, where r<R, is given by
V = (q(3R^2 - r^2))/8piEoR^3).

2. A pendulum is hung from the higher of two large horizontal plates. The pendulum consists of a small conducting sphere of mass m and charge +q and an insulating thread of length L. What is the period of the pendulum of a uniform electric field E is set up between the plates by

(a) charging the top plate negatively and the lower plate positively
(b) and vice versa?

3. A uniform upward electric field E of magnitude 2.00 x 10^3 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 10.0cm and separation d = 2.00cm. An electron is then shot between the plates from the left edge of the lower plate. The intial velocity of the electron makes an angle 45 degrees with the lower plate and has a magnitude 6.00 x 10^6 m/s.

(a) Will the electron strike one of the plates?
(b) If so, which plate and how far horizontally from the left edge will the electron stike?
 
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  • #2
what work have you done on these so far? Most people will want to see some work before they help you too much, here is a hint for number 1 though:

First, there should be some more specification in the question about the V=0 part, V is a function of x, is it V(0) = 0 or V(infinity) = 0 ? You can pick either one without any problems, because only the change in potential matters, however, you will get different forms of answers. It looks like in this problem you want to set V(0) = 0.

So now, look at the definition that you have for potential. And also use your knowledge of Gauss's Law in order to allow you to determine the charge that is contained when you are at any radial point on the sphere.

~Lyuokdea
 
  • #3
So here's what I attempted with question 1

For r > R the sphere behaves as a point charge

V(r) = Q/4piEor therefore at the surfaces, potential V(R) = Q/4piEor

Va - Vb = Q/4piEor^3 [(rb^2/2) - ra^2/2)]

for rb= R, Vb = Q/4piEoR

Va = Q/4piEoR = Q/8piEor^3 (R^2 - ra^2) + 2Q/8piEoR

that is Va = Q/8piEoR - (Qra^2/8piEor^3) + 2Q/8piEoR
 

FAQ: Electric fields and electric potential

What is an electric field?

An electric field is a region in which a charged particle experiences a force due to the presence of other charged particles. It is represented by a vector quantity and is measured in newtons per coulomb (N/C).

How is an electric field calculated?

The electric field at a particular point is calculated by dividing the force experienced by a test charge placed at that point by the magnitude of the test charge. Mathematically, it can be represented as E = F/q, where E is the electric field, F is the force, and q is the test charge.

What is electric potential?

Electric potential is a measure of the potential energy of a charged particle in an electric field. It is defined as the work done per unit charge in bringing a test charge from infinity to a particular point in the electric field. It is measured in volts (V).

How is electric potential related to electric field?

Electric potential and electric field are closely related. The electric field is the gradient of electric potential, meaning it is the rate of change of electric potential with respect to distance. Mathematically, the relationship can be represented as E = -∇V, where E is the electric field, V is the electric potential, and ∇ is the gradient operator.

How can electric potential be calculated?

Electric potential is calculated by using the formula V = kq/r, where V is the electric potential, k is the Coulomb's constant, q is the charge, and r is the distance between the charged particle and the point where the potential is being measured. Alternatively, it can also be calculated by integrating the electric field over a specific distance.

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