Electric Forces and Fields questions,

In summary: Just remember to use the Pythagorean theorem to find the distance between the charges and the inverse square law to calculate the electric force. In summary, the conversation discussed two questions related to electric forces and fields. The first question asked for the distance between two charges in electrostatic equilibrium, while the second question involved calculating the magnitude of the electric force on a charge in a coordinate plane. The conversation also mentioned using the equations for electric force and the Pythagorean theorem to solve these problems.
  • #1
WGman
2
0
Electric Forces and Fields questions, please help!

1. Charge A and Charge B are 2.2 m apart. Charge A is 1.0 Coulomb, Charge B is 2.0 Coulombs, and Charge C is 2.0 Coulombs and is located between Charges A and B and is in electrostatic equilibrium. How far from Charge A is Charge C?

2. Two equal positive charges, both q= 2.0 x 10^ -6 Coulombs, interact with a third charge, Q= 4.0 x 10^ -6 Coulombs. What is the magnitude of the electric force on Q? (In a coordinate plane, the two "q"s are on the y axis: the first one is .3 meters above the origin and the second one is .3 meters below the origin. Q is located .4 meters right of the origin (on the +x axis). this all makes one triangle, or two right triangles side by side.)




2. E= Electric Force/q Electric Force= Kc x q1xq2/(r^2) E= Kc x q/(r^2) Kc= 8.99 x 10^9



3. I haven't gotten much accomplished besides a picture, I'm completely lost! D:
 
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  • #2


Welcome to PF, WGman. It would be nice to see your diagram and work. You could scan it, photograph it or sketch it in a paint program. Upload the jpg file to a service such as photobucket and paste a link in your post here.

Charge C will have two forces on it, one to the left and one to the right so your beginning equation will be
F1 + F2 = 0
Fill in the detailed formula for the electric force in each case. One of the distances will be unknown, say x. The other will be (2.2 - x).

Post your work if you need more help!
 
  • #3


thanks for your help so far!
so now i have set that up, but how can i rearrange the equation to get x once i plug in the variables? thanks!

and for the second one so far i am splitting the triangle formed into two right triangles, with the legs on the x and y axis. once i find the magnitude of the force not on the axis (using r as the hypotenuse, the distance between q and Q) and using sin and cos to find the components before adding them!
 
  • #4


Your equation will have only the one unknown, x. Solve it as you would any simple equation!

Your plan for the second one sounds good.

It is hard to help when I can't see your work.
 
  • #5


Hello, I am a scientist and I would be happy to help you with your questions on electric forces and fields. Let's start with the first question.

1. To determine the distance between Charge A and Charge C, we can use the equation for electrostatic equilibrium, which states that the net force on an object in equilibrium is zero. This means that the forces between Charge A and Charge C, and between Charge B and Charge C, must be equal in magnitude and opposite in direction. We can set up the equation as follows:

FAC = FBC
kQ1Q2/dAC^2 = kQ2Q3/dBC^2

where k is the Coulomb constant, Q1 and Q2 are the charges of A and B respectively, and Q3 is the charge of C.

Substituting the given values, we get:

(9 x 10^9)(1)(2)/(dAC^2) = (9 x 10^9)(2)(2)/(2.2 - dAC)^2

Solving for dAC, we get a distance of 1.1 m from Charge A.

2. To find the magnitude of the electric force on Q, we can use the equation for electric force, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. We can set up the equation as follows:

F = kQq/r^2

where k is the Coulomb constant, Q and q are the two equal positive charges, and r is the distance between them.

Substituting the given values, we get:

F = (9 x 10^9)(2 x 10^-6)(2 x 10^-6)/(0.4)^2

Solving for F, we get a force of 22.5 x 10^-3 N.

3. For the third question, it seems like you are struggling with visualizing the problem. I would suggest drawing a diagram to help you understand the situation better. From the given information, we can see that we have two right triangles with equal sides of 0.3 m, and we need to find the hypotenuse of each triangle. Once we have the hypotenuse, we can use the Pythagorean theorem to find the distance between the two positive charges. I hope this helps. Let me know if you have
 

FAQ: Electric Forces and Fields questions,

1. What is an electric force?

The electric force is a fundamental force of nature that exists between two charged particles. It can be attractive or repulsive, depending on the charge of the particles.

2. What is an electric field?

An electric field is a region of space around a charged object where the electric force can be felt by other charged objects. It is represented by lines of force that indicate the direction and strength of the force at different points in the field.

3. How is the strength of an electric field measured?

The strength of an electric field is measured by the force it exerts on a unit charge placed in the field. This is known as the electric field strength and is measured in newtons per coulomb (N/C).

4. What is the relationship between electric force and distance?

The electric force between two charged particles is inversely proportional to the square of the distance between them. This means that as the distance between the particles increases, the force decreases.

5. How do electric forces and fields affect charged particles?

Electric forces and fields can cause charged particles to accelerate, change direction, or remain at rest. They can also cause charged particles to attract or repel each other, depending on the direction of the electric force and the charges of the particles.

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