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blee22
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Homework Statement
You start at a distance r from a point charge. The electric potential is 4500V at that point, and the electric field is 2.3x105N/C. a) What is r? b) What is the electric potential and magnitude of the electric field at a distance of r/4?
Homework Equations
v= kq/r E=kq/r^2 substitute everything and get q= v^2/kE?
r=kq/v
solve for q which will then allow you to solve for r?
The Attempt at a Solution
V = 4500, k = 8.9x10^9 and E = 2.3x10^5 that will give us a q
This q will then be put into the equation r=kq/v and that will give you the answer for a?
Part b would you take that distance solve for the magnitude and e-field?