- #1
prolong199
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could someone please lead me in the right direction with this question. I am confused about the time varying force in determining the work done
A time-varying force acts on a 5 kg mass yielding a displacement
x = 5t - 8t2 (x in m). The work done by the force between the times
t = 0 and t = 5s, is
thanks.
A time-varying force acts on a 5 kg mass yielding a displacement
x = 5t - 8t2 (x in m). The work done by the force between the times
t = 0 and t = 5s, is
thanks.