- #1
felipeek
- 4
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Hello everyone,
Imagine two points that have a Electric Potential Difference of 10V and they are connected through a conductor wire. Let's call these points A and B:
Now imagine we have a charge on A of 1C. To move the charge to B, we need to make a work of 10J, right?
So, now, imagine the charge is on B. This means that the charge has 10J of Electric Potential Energy. Now, we let the charge goes through the wire, naturally. When the charge reaches point A, the potential energy will be reduced to 0, right?
The electric potential energy was converted to what? Kinetic energy? heat energy?
Now, what bothers me so much. Imagine now that we put a resistor between A and B:
Imagine the resistence of the resistor is 10ohm, for example. The wire is a good conductor, so the resistence is almost 0.
Again, imagine 1C going from B to A.
In this situation, the voltage drop of the resistor would be almost 10V, right? This is because the potential difference between B and A is also 10V and the resistence of the wire is almost 0ohm.
In the picture A a charge that travels between B and A "used" 10J of energy to do it. Regardless of how the energy was converted, it was done. Going from B to A make the charge to lose 10J of potential energy.
In the picture B, there is a resistor between A and B. The resistor consumes almost 10J of energy. This is ok, since the resistor is naturally an energy-absorber - it will transform the electric energy into heat energy or whatever. But what I can't understand is: How now when the charge travels through the wire it almost doesn't lose electric potential energy? The path between A and the negative terminal of the resistor have a voltage drop almost imperceptible, the same with the path between the positive terminal of the resistor and B.
In the first scene, the charge lost 10J of potential energy just passing through the wire, without any resistor. In the second scene, only because a resistor was added to the circuit, all the voltage drop was directed to the resistor, and the wire became almost insignificant. Could someone explain me why this happens?
If you guys could point all errors I made here and explain my question, I'll be so thankful. Thank you very much
Imagine two points that have a Electric Potential Difference of 10V and they are connected through a conductor wire. Let's call these points A and B:
Now imagine we have a charge on A of 1C. To move the charge to B, we need to make a work of 10J, right?
So, now, imagine the charge is on B. This means that the charge has 10J of Electric Potential Energy. Now, we let the charge goes through the wire, naturally. When the charge reaches point A, the potential energy will be reduced to 0, right?
The electric potential energy was converted to what? Kinetic energy? heat energy?
Now, what bothers me so much. Imagine now that we put a resistor between A and B:
Imagine the resistence of the resistor is 10ohm, for example. The wire is a good conductor, so the resistence is almost 0.
Again, imagine 1C going from B to A.
In this situation, the voltage drop of the resistor would be almost 10V, right? This is because the potential difference between B and A is also 10V and the resistence of the wire is almost 0ohm.
In the picture A a charge that travels between B and A "used" 10J of energy to do it. Regardless of how the energy was converted, it was done. Going from B to A make the charge to lose 10J of potential energy.
In the picture B, there is a resistor between A and B. The resistor consumes almost 10J of energy. This is ok, since the resistor is naturally an energy-absorber - it will transform the electric energy into heat energy or whatever. But what I can't understand is: How now when the charge travels through the wire it almost doesn't lose electric potential energy? The path between A and the negative terminal of the resistor have a voltage drop almost imperceptible, the same with the path between the positive terminal of the resistor and B.
In the first scene, the charge lost 10J of potential energy just passing through the wire, without any resistor. In the second scene, only because a resistor was added to the circuit, all the voltage drop was directed to the resistor, and the wire became almost insignificant. Could someone explain me why this happens?
If you guys could point all errors I made here and explain my question, I'll be so thankful. Thank you very much