Electric Potential Homework: Circle of Radius 5 cm

In summary, the wire carrying a charge density of λ=.1c/m is bent into a circle of radius r = 5 cm. The electric potential at the center of the circle can be calculated using the equation V=Q/(4πε0r) where Q=2πrλ. The "r" drops out in this equation, resulting in a simplified solution. Alternatively, the potential can also be computed by integrating the electric field from the center to infinity.
  • #1
rgold
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Homework Statement


A wire carrying a charge density of λ=.1c/m is bent into a circle of radius r = 5 cm. What is the electric potential at the center of the circle

Homework Equations

The Attempt at a Solution


λ/2Ԑ0 is this right? i do not really understand it or where my radius went
 
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  • #2
It does appear the potential is ## V=Q/(4*\pi*\epsilon_o*r) ## and ## Q=2*\pi*r*\lambda ## A more lengthy approach to compute V would be to integrate the electric field from the center to infinity. Anyway, I think you can see how the "r" dropped out. Your answer is correct. The potential from a distribution of charges is the sum of all the potentials from infinitesimal elements of these charges.
 

FAQ: Electric Potential Homework: Circle of Radius 5 cm

What is electric potential?

Electric potential is the amount of electric potential energy per unit charge at a certain point in an electric field.

How do you calculate electric potential?

Electric potential can be calculated by dividing the electric potential energy by the charge at a certain point in an electric field.

What is the equation for electric potential?

The equation for electric potential is V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge, and r is the distance from the charge.

What is the unit for electric potential?

The unit for electric potential is volts (V).

How does the circle of radius 5 cm relate to electric potential?

In the context of this homework, the circle of radius 5 cm represents a point in an electric field at which the electric potential is being calculated. The distance from this point to the charge is 5 cm, which is used in the electric potential equation.

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