Electric potential outside an insulator in a uniform field

In summary, the problem involves finding the potential outside an insulating sphere placed in an Ohmic material with uniform current density. The Laplace equation applies outside the sphere, with boundary conditions determined by the continuity of electric field components at the boundary. The current is expected to flow tangentially around the sphere, with no current going inside due to the insulating nature of the sphere. The boundary condition at the outside surface of the sphere can be determined by considering the constancy of any free surface charge on the sphere.
  • #1
frimidis
2
0

Homework Statement


An Ohmic material with some conductivity has a uniform current density J initially. Let's say the current is flowing in the direction of the z-axis. A small insulating sphere with radius R is brought inside the material. Find the potential outside the sphere.

Homework Equations


Continuity equation $$\nabla\cdot J=-\dfrac{\partial\rho}{\partial t}$$
Ohmic material electric field $$J=\sigma E$$
Maxwell's equations boundary conditions


$$E_1^{\parallel}-E_2^{\parallel}=0$$


and

$$\epsilon_1E_2^{\perp}-\epsilon_2E_2^{\perp}=\sigma_f$$

Presumably there's no free charge so the charge density of it is 0.

The Attempt at a Solution


I assume the insulator will make the current flow such that there is no change in the charge density. Hence $$\nabla\cdot J=0$$
and so $$\nabla\cdot E=0$$
and so the electric potential obeys the Laplace equation outside the sphere
$$\nabla^2V=0$$

I know the general solution for the Laplace equation in spherical coordinates when there's azimuthal symmetry. I'm stuck with the boundary conditions.

1)
The first one is easy. Far away from the insulator the potential is just due to the electric field that causes the current to flow in the Ohmic material so far away in spherical coordinates
$$V_{far}=-\dfrac{J}{\sigma}z=-\dfrac{J}{\sigma}r\cos\theta$$
2)
I'm unsure about the other boundary conditions. And they seem to be only about the discontinuity of the electric field components at the boundary of the sphere. Apparently we can/need only consider one of the electric field components because we don't have enough information what is going on in the insulator. Is the electric field supposed to be 0 inside it or does it just mean that there doesn't flow any current? I'm stuck at the boundary conditions and I'm not sure how exactly is the current supposed to be affected by the presence of the insulator. Does the current just flow around it tangentially? Presumably no current can go inside as it is an insulator.

Thanks
 
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  • #2
frimidis said:
2) Does the current just flow around it tangentially? Presumably no current can go inside as it is an insulator.
Yes. In the steady state, any free surface charge on the sphere must be constant in time. What does this tell you about the radial component of ##\vec J## at the outside surface of the sphere? In turn, what boundary condition on ##V## does this imply at the outside surface of the sphere?
 

FAQ: Electric potential outside an insulator in a uniform field

What is electric potential?

Electric potential is a measure of the potential energy of a charged particle in an electric field. It is also known as voltage and is measured in volts (V).

What is an insulator?

An insulator is a material that does not allow electricity to flow through it easily. This is because the electrons in an insulator are tightly bound to their atoms and cannot move freely.

What is a uniform field?

A uniform field is an electric field that has the same strength and direction at all points. This means that the electric potential at any point in the field will be the same.

How does an insulator behave in a uniform electric field?

In a uniform electric field, an insulator will not conduct electricity. This is because the charges in the insulator are not free to move and therefore cannot create a current.

What is the electric potential outside an insulator in a uniform field?

The electric potential outside an insulator in a uniform field is constant. This means that the electric potential at any point outside the insulator will be the same, regardless of its distance from the insulator.

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