- #1
CalvinandHobbes
- 4
- 3
- Homework Statement
- Calculation of potential electrical energy in a siphon water pipe
- Relevant Equations
- Ey=Eo x Vy/Vo x adjustment coefficients
Calculation of the potential electrical energy generation of a siphon pipe, emptying an enclosed reservoir and end of siphon pipe connected to a pelton turbine with efficiency of 75%
Known inputs:
Height difference of siphon(Hd) = 4,5m
Height lift of Siphon (Hu) = 6m
Total siphon pipe length 10.5m
Pipe internal diameter 28mm
Friction loss coefficient : 0.00184
Head loss at inlet resistance coefficient:0.464
Resistance coefficient at bend siphon: 1.4
Maximum instantaneous power from flow:245.24W
Minmum instantaneous power from flow:64.31W
Integral instantaneous power from flow:245.24W
Maximum Vacuum:8m
Average energy generation on emptying reservoir: 2940j
Time to empty reservoir: 81415.89s
Reservoir volume: 168.713m3
Reduction coefficient: 0.92
generator effeciency coefficient: 0.8
Turbine efficiency: 75%
Solution:
2940 x 81415.89/1000x.000277778 x 0.92 x 0.8 x .75 = 36.7kWh
Known inputs:
Height difference of siphon(Hd) = 4,5m
Height lift of Siphon (Hu) = 6m
Total siphon pipe length 10.5m
Pipe internal diameter 28mm
Friction loss coefficient : 0.00184
Head loss at inlet resistance coefficient:0.464
Resistance coefficient at bend siphon: 1.4
Maximum instantaneous power from flow:245.24W
Minmum instantaneous power from flow:64.31W
Integral instantaneous power from flow:245.24W
Maximum Vacuum:8m
Average energy generation on emptying reservoir: 2940j
Time to empty reservoir: 81415.89s
Reservoir volume: 168.713m3
Reduction coefficient: 0.92
generator effeciency coefficient: 0.8
Turbine efficiency: 75%
Solution:
2940 x 81415.89/1000x.000277778 x 0.92 x 0.8 x .75 = 36.7kWh