How Does an Electromagnetic Brake System Work for a Truck?

[wikicheema]

Homework Statement

Design and Perform calculation for an Electromagnetic Brake system of a truck having 3 Axils assuming that each axil carries equal load. The truck is carrying a load of 30000 Kg and the weight of truck is 6000 Kg and moving with 100km/h speed before the brake is applied.
calculate.
1) Braking Torque
2) Magnetic Filed required to reduce the vehicle speed upto 20 km/h
3) current required
4) suitable material
5) design the brake

Homework Equations

how to calculate current required

The Attempt at a Solution

I have calculated Braking torque and magnetic field. which is shared on following links.
The torque I got , is too much, i think.. please tell me if I am wrong

https://rapidshare.com/files/3568781...led_folder.zip
https://rapidshare.com/files/2134776...d_folder_2.zip

 

[mark726]

Thank you for your question regarding the design and calculation of an electromagnetic brake system for a truck. I am happy to assist you with this problem.

1) Braking Torque:
The braking torque of an electromagnetic brake system can be calculated using the following equation:

T = μ * B * A * N

Where:
T = braking torque (Nm)
μ = coefficient of friction between the brake pads and the brake disc
B = magnetic field strength (T)
A = effective area of the brake disc (m^2)
N = number of turns in the coil

To calculate the coefficient of friction, you will need to consider the materials used for the brake pads and the brake disc. For example, if the brake pads are made of ceramic and the brake disc is made of steel, the coefficient of friction would be around 0.3.

Assuming an effective area of 0.1 m^2 and 100 turns in the coil, the braking torque can be calculated as:
T = 0.3 * B * 0.1 * 100 = 3B Nm

2) Magnetic Field Required:
To reduce the vehicle speed from 100 km/h to 20 km/h, we need to calculate the change in kinetic energy of the truck. This can be calculated using the following equation:

ΔKE = 0.5 * m * (vf^2 - vi^2)

Where:
ΔKE = change in kinetic energy (J)
m = mass of the truck (kg)
vf = final velocity (m/s)
vi = initial velocity (m/s)

Converting the initial and final velocities to m/s, we get:
vi = 100 km/h = 27.8 m/s
vf = 20 km/h = 5.6 m/s

Substituting these values, we get:
ΔKE = 0.5 * (30000 + 6000) * (5.6^2 - 27.8^2) = -3.5 * 10^6 J

This change in kinetic energy needs to be dissipated by the brake system, which is equal to the work done by the magnetic field. The work done by the magnetic field can be calculated using the following equation:

W = -∫B * dM

Where:
W = work done by the magnetic field (J)
B = magnetic field strength (