Then I suggest that you write each of the vectors involved in unit vector notation, add them to get the Lorentz force as per the equation you posted and finally find its magnitude. It will be the square root of the sum of the components squared and will depend on how you chose the three vectors.Sat-P said:
Electromagnetic force is one of the four fundamental forces of nature, responsible for the interactions between charged particles. It is described by Maxwell's equations and can manifest as both electric and magnetic forces, influencing the motion of charged particles, such as electrons and protons.
A positively charged particle experiences a force when it is placed in an electric field or a magnetic field. The direction of this force is determined by the charge of the particle and the direction of the field. In an electric field, the force acts in the direction of the field lines, while in a magnetic field, the force is perpendicular to both the velocity of the particle and the magnetic field direction, following the right-hand rule.
The electromagnetic force (F) acting on a charged particle can be calculated using the Lorentz force equation: F = q(E + v × B), where q is the charge of the particle, E is the electric field, v is the velocity of the particle, and B is the magnetic field. The term v × B represents the magnetic force component, which is perpendicular to both the velocity and the magnetic field.
Yes, a positively charged particle will experience a net force in a uniform electric field. The force will be constant in magnitude and direction, acting in the same direction as the electric field lines. This results in the particle accelerating in that direction, according to Newton's second law of motion.
When a positively charged particle moves through a magnetic field, it experiences a magnetic force that is perpendicular to both its velocity and the direction of the magnetic field. This force causes the particle to undergo circular or helical motion, depending on its angle of entry into the magnetic field, and does not do work on the particle, meaning it does not change the particle's speed, only its direction.