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whynot314
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An electron in the ground state of a one-dimensional infinite square well of width 1.10 nm is
illuminated with light of wavelength 600 nm. Into which quantum state is the electron excited?
ok so I first calculated the engery of the electron in the first ground state of the square well using
[itex]\frac{1240^{2}}{8*511000*1.10^{2}}[/itex]
I get .310 eV
Then i calculate the energy of the photon
[itex]\frac{1240}{600}[/itex]
and i get 2.066 eV
Then i do
2.066=[itex]\frac{1240^{2}}{8*511000*1.10^{2}}[/itex]*[itex]n^{2}[/itex]-.310
and solve for n i get the 3rd state. that answer says it should be in the same state n=1, I am not sure what I am doing wrong.
illuminated with light of wavelength 600 nm. Into which quantum state is the electron excited?
ok so I first calculated the engery of the electron in the first ground state of the square well using
[itex]\frac{1240^{2}}{8*511000*1.10^{2}}[/itex]
I get .310 eV
Then i calculate the energy of the photon
[itex]\frac{1240}{600}[/itex]
and i get 2.066 eV
Then i do
2.066=[itex]\frac{1240^{2}}{8*511000*1.10^{2}}[/itex]*[itex]n^{2}[/itex]-.310
and solve for n i get the 3rd state. that answer says it should be in the same state n=1, I am not sure what I am doing wrong.