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jannos
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Homework Statement
A 12V battery has an internal resistance of 6Ω.
a) If this battery is connected to a 10Ω load, calculate the power dissipated by the load.
b) Draw a graph showing how the terminal voltage of the battery and the current it can supply vary with load.
c) Derive a value for the maximum power this battery can deliver. What load resistance should be applied to the battery for this to occur?
Homework Equations
V=I(R+r)
P=IW
V=IR
I=v/(R+r)
The Attempt at a Solution
I have completed part a) My answer is 14.4W
I am stuck on part 2, I have made a table in excel which I will use to plot a graph. I am slightly confused. I am probably wrong here but I have established that the equation V=I(R+r) is used for working out the terminal voltage and current supplied across a load.
If this is the case then only one variable can be worked out at one time (with a varying load), either terminal voltage or the current supplied.
Therefor do I draw 2 separate graphs: 1 of a 'load' vs 'terminal voltage' with the current constant. Another of 'load' vs 'current' with the terminal voltage constant?
Or am I not understading it properly?
My intention is to derive the maximum power of part C after I have suitable graphs for part B.
Thanks