- #1
tanaygupta2000
- 208
- 14
- Homework Statement
- Consider eight electrons in a one dimensional box of length 'a' extending from x = 0 to x = a. What is the minimum allowed total energy using Pauli's exclusion principle for the system (m = mass of electron)?
- Relevant Equations
- Energy of particles in a 1D box = n^2 h^2/ (8mL^2)
For the given problem, I know that the quantized energy for the particles in a 1D box is given by -
E(n) = n^2 h^2/ (8mL^2)
Here m = mass of electron
L = Length of the box = a
Now, since there are 8 electrons, but only 2 can occupy one energy level,
so I used n^2 = (1)^2 + (2)^2 = 1 + 4 = 5
So for a 'pair' of electrons, E = 5h^2/8ma^2
Hence total energy should be (since there are 8 electrons) = 4 * 5h^2/8ma^2
= 5h^2/2ma^2
Is my approach correct for attempting the question ?
Please guide.
E(n) = n^2 h^2/ (8mL^2)
Here m = mass of electron
L = Length of the box = a
Now, since there are 8 electrons, but only 2 can occupy one energy level,
so I used n^2 = (1)^2 + (2)^2 = 1 + 4 = 5
So for a 'pair' of electrons, E = 5h^2/8ma^2
Hence total energy should be (since there are 8 electrons) = 4 * 5h^2/8ma^2
= 5h^2/2ma^2
Is my approach correct for attempting the question ?
Please guide.