Electrostatic Potential Energy of a Conducting Sphere

In summary, the total electrostatic potential energy of a conducting sphere with uniform charge distribution on its surface can be calculated using the formula W = kQ^2/2r, where Q is the total charge, r is the radius of the sphere, and k is a constant. If the question is rephrased to include a charge density, p, instead of a total charge, Q, the formula would become W = kQ^2/2rv, where v is the volume of the sphere.
  • #1
George3
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Homework Statement


Determine the total electrostatic potential energy of a conducting sphere of radius r_0 that carries a total charge Q distributed uniformly on its surface. Give your answer in terms of Q, r_0, epsilon_0 and appropriate constants.


Homework Equations





The Attempt at a Solution



I know that U = QV and I know that V = kQ/r. I tried to answer it as U = (1/(4pi*epsilon_0))*Q^2/r_0 but that seems to be incorrect. Can anyone point me in the right direction?
 
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  • #2
The electrostatic potential energy of the sphere is equal to the work done while it is charged.
If there is q charge on the sphere, the potential is kq/r0 on it surface. The work needed to move a charge dq from infinity to the surface of the sphere is:

[tex]

dW=kq*dq/r_0 [/tex]

To get the whole work, you have to integrate from q=0 to q=Q.

ehild
 
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  • #3
So if you integrate dW = kq *dq/r you end up getting W = k/r * the integral of q *dq from 0 to Q. Which just ends up being W = kQ^2/2r right?
 
  • #4
George3 said:
So if you integrate dW = kq *dq/r you end up getting W = k/r * the integral of q *dq from 0 to Q. Which just ends up being W = kQ^2/2r right?

Yes, but with r0, the radius of the sphere.

ehild
 
  • #5
i have a question similar to this. I was wondering if the question was rephrased to say that the sphere has a charge density, p, instead of a charge q how you would answer it?

Would simply become a Q/(volume of sphere) instead of q in your integral equation with everything else remaining the same?

Ps. sorry if this is not the correct format to ask a question (im new on the forum). If you guys want me to make a new thread please let me know thanks!
 

FAQ: Electrostatic Potential Energy of a Conducting Sphere

What is electrostatic potential energy?

Electrostatic potential energy is the energy stored in an object due to its position in an electric field. It is a type of potential energy that arises from the interaction between electrically charged particles.

How is electrostatic potential energy calculated for a conducting sphere?

The electrostatic potential energy of a conducting sphere can be calculated using the formula U = Q² / (8πε₀r), where Q is the charge of the sphere, r is the distance from the center of the sphere, and ε₀ is the permittivity of free space.

How does the charge of a conducting sphere affect its electrostatic potential energy?

The electrostatic potential energy of a conducting sphere is directly proportional to the square of its charge. This means that as the charge of the sphere increases, its electrostatic potential energy also increases.

Why is the electrostatic potential energy of a conducting sphere important?

The electrostatic potential energy of a conducting sphere is important because it helps us understand the behavior of charged particles and their interactions with electric fields. It also plays a significant role in various applications, such as in the design of electric circuits and devices.

How does the distance between two conducting spheres affect their electrostatic potential energy?

The electrostatic potential energy between two conducting spheres is inversely proportional to the distance between them. This means that as the distance between the spheres increases, their electrostatic potential energy decreases. This relationship is known as the inverse-square law.

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