Electrostatic Potential for Two Concentric Cylindrical Shells

In summary: At r=a, V(r) is +q/4piE0.For all values of r greater than a, V(r) decreases linearly.For r=a, V(r) is at zero potential.Between a and b, V(r) has the magnitude of q/4piE0, but the direction is opposite.For r>b, V(r) has the magnitude of q/4piE0 and the direction is the same.
  • #1
sweetdion
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Homework Statement


Two very long hollow conducting cylindrical shells are situated along the x-axis. The shells are concentric and have negligible thickness. The inner shell has a radius a and a linear charge density +lambda, while the outer shell has a radius b and a linear charge density -lambda. Take the zero of electrostatic potential to be at r = 0. The coordinate r measures the distance from the common axis of the two cylinders in a region far from either end.

a) Determine the electrostatic potential V(r) for all values of r
b) Sketch V(r) vs. r for all r
c) Determine the potential difference DeltaV between r=a and r=b
d) If a positive charge +q is released from rest at r=a, what will be its kinetic energy when it reaches the outer cylinder at r=b.


Homework Equations


V(r)=q/4piE0r
Delta V=Vb-Va=q/4PiE0*(1/rb-1/ra)
Ke=1/2mv^2
U=kq1q2/r
KEf=Ui


The Attempt at a Solution


a) at r=a
V=q/4piE0a

at r=b
V=q/4piE0b

b) as the radius increases the potential goes down. It starts at some positive y value and ends at some negative y value.

c)Delta V=Vb-Va=q/4PiE0*(1/b-1/a)

d) U=kq1q2/a
1/2mv^2=kq1q2/r
v^2=2kq1q2/mr
v=(2kq1q2/mr)^1/2
 
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  • #2
I'm just wanting to know if i got this right
 
  • #3
sweetdion said:

Homework Statement


Two very long hollow conducting cylindrical shells are situated along the x-axis. The shells are concentric and have negligible thickness. The inner shell has a radius a and a linear charge density +lambda, while the outer shell has a radius b and a linear charge density -lambda. Take the zero of electrostatic potential to be at r = 0. The coordinate r measures the distance from the common axis of the two cylinders in a region far from either end.

Homework Equations


V(r)=q/4piE0r

The formula you quoted refers to a point charge. These are very long cylinders.

ehild
 
  • #4
V(r)= 1/4piE0 Int dq/r
 
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  • #5
Part C)

EA=Qenc/E0
E=lamda/PirE0
Delta V=-lamda/PiE0 Int dr/r
Delta V= lamda/PiE0 ln(b/a)
 
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  • #6
You have started part C well, but it is still wrong.

The first questions were:

"a) Determine the electrostatic potential V(r) for all values of r
b) Sketch V(r) vs. r for all r"

So what is the potential for r<a? for r>b?

ehild
 
  • #7
what equation am i supposed to use to figure out the potential? so confused.

V (r) = 1/4PiE0 * Int dq/r ?
 
  • #8
Find the electric field first. What is it inside the inner cylinder? Between a and b? for r>b? Use Gauss' law.
For r<0, the enclosed charge is 0. If a<r<b, the enclosed charge is +lambda *Length of the cylinder. For a cylinder with r>b, the enclosed charge is 0. E is the negative gradient of the potential. What is the potential like if E=0?

ehild
 
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FAQ: Electrostatic Potential for Two Concentric Cylindrical Shells

What is the formula for calculating the electrostatic potential for two concentric cylindrical shells?

The formula for calculating the electrostatic potential for two concentric cylindrical shells is V = kQ/2πεL, where V is the potential difference, k is the Coulomb's constant, Q is the charge on the inner shell, ε is the permittivity of the medium between the two shells, and L is the distance between the two shells.

How does the charge on the inner shell affect the electrostatic potential?

The electrostatic potential is directly proportional to the charge on the inner shell. This means that as the charge on the inner shell increases, the potential difference between the two shells also increases.

What is the significance of the distance between the two concentric cylindrical shells in the electrostatic potential?

The distance between the two shells, denoted by L, plays a crucial role in determining the electrostatic potential. As L increases, the potential difference decreases, and as L decreases, the potential difference increases. This is because the electric field strength between the two shells is inversely proportional to the distance between them.

How does the permittivity of the medium between the two shells affect the electrostatic potential?

The permittivity of the medium between the two shells, denoted by ε, also plays a significant role in determining the electrostatic potential. As ε increases, the potential difference decreases, and as ε decreases, the potential difference increases. This is because the electric field strength is directly proportional to the permittivity of the medium.

What is the unit of measurement for the electrostatic potential?

The unit of measurement for the electrostatic potential is volts (V). This is because potential difference is the measure of energy per unit charge, and the SI unit for energy is joules (J), and charge is measured in coulombs (C). Therefore, V = J/C.

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