- #1
hellojojo
- 4
- 0
Hello, so this was a past assignment question that I attempted. I got the right answer but in an incorrect way (I guess my thinking was not based on the concept?)
1. Homework Statement
Three point charges of charge Q = 10 https://maple-ta.uwaterloo.ca/mapleta/tmp/am/dh/gm/finnniaffjjcdncgjfhcnmebcf.gif and mass m = 25 g are located at the corners of an equilateral triangle, with side length 4 cm. One of the charges is let go. Gravity should be ignored.
What will its speed be when it is at infinity?
The answer was 56 m/s
3. The Attempt at a Solution
My solution was:
E1 =E2= Kq/r = ((8.99x10^9)(1x10^-5)(1x10^-5))/(0.04) = 22.475J
Then the x component was:
E1(x)= 22.475J*sin 30=11.2375
E2 (x)=22.475J*-sin 30=-11.2375
E1(y)=22.475J*cos30=19.46
E2(y)=22.475J*cos30=19.46
THen using Ke=1/2mv^2
v=56m/s
I used components instead of the electromagnetic force equation between two charges.
This is wrong or an incorrect way of thinking and I should've used the equation:
(kQQ/r-3KQQ/r)
Can someone explain to me what is going on and how this equation explains what is happening between the three forces.
Thanks
1. Homework Statement
Three point charges of charge Q = 10 https://maple-ta.uwaterloo.ca/mapleta/tmp/am/dh/gm/finnniaffjjcdncgjfhcnmebcf.gif and mass m = 25 g are located at the corners of an equilateral triangle, with side length 4 cm. One of the charges is let go. Gravity should be ignored.
What will its speed be when it is at infinity?
The answer was 56 m/s
3. The Attempt at a Solution
My solution was:
E1 =E2= Kq/r = ((8.99x10^9)(1x10^-5)(1x10^-5))/(0.04) = 22.475J
Then the x component was:
E1(x)= 22.475J*sin 30=11.2375
E2 (x)=22.475J*-sin 30=-11.2375
E1(y)=22.475J*cos30=19.46
E2(y)=22.475J*cos30=19.46
THen using Ke=1/2mv^2
v=56m/s
I used components instead of the electromagnetic force equation between two charges.
This is wrong or an incorrect way of thinking and I should've used the equation:
(kQQ/r-3KQQ/r)
Can someone explain to me what is going on and how this equation explains what is happening between the three forces.
Thanks
Last edited by a moderator: