Elevator Problem: Find Tension in Cable

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To solve the elevator problem, the weight of the elevator is 1400 kg, and it initially moves downward at 12 m/s before coming to a stop over a distance of 41 m. The acceleration calculated is 1.75 m/s², which is used to determine the tension in the cable. The formula T = m(a + g) is applied, resulting in a tension of 16,170 N. This calculation effectively incorporates both the acceleration and gravitational force acting on the elevator.
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Homework Statement


Elevator weighs 1400 kg with an initial velocity of 12 m/s (moving downward). With a constant acceleration, the elevator comes to a stop in 41 m. What is the tension on the elevator cable?


Homework Equations



T=m(a+g)

The Attempt at a Solution



I'm having trouble finding the acceleration of the elevator.
 
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I got it, a=1.75 m/s\hat{2}

by v\hat{2}=v\check{i}\hat{2}+2a(\Deltax)

T=16170 N
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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